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monitta
3 years ago
13

H(x) = x^2 + 1 k(x) = x – 2 (h + k)(2)=?

Mathematics
1 answer:
likoan [24]3 years ago
6 0
First we will compute the h+k and then multiply the result by 2.
To add polynomials, we add terms whose variables are alike, for example:
we add the coefficients of x^2 together, the coefficients of x together and so on.

Therefore:
h + k = x^2 + 1 + x - 2 = x^2+x-1

Now, we will multiply this answer by 2 to get the final answer:
2(h+k) = 2(x^2+x-1) = 2x^2 + 2x -2
You might be interested in
Y=23x+5 and<br><br> y=x+3<br><br> what is the solution
kondor19780726 [428]

Answer:

I solved this like you would a system of equations - if that is not the answer you need LMK

Point form:

(- 1/11, 32/11)

Equation Form:

x = -1/11, y = 32/11

Step-by-step explanation:

8 0
3 years ago
The area of Kylie's room is 400 square feet. The width of her room is 20 feet. What is the length of her room?
zavuch27 [327]

Answer:

length=20 (Sorry if this is wrong)

Step-by-step explanation:

400÷20=20

3 0
2 years ago
Add [1/-4 3/5] [-2/6 -2/4]
brilliants [131]

Answer:

​25/138

Step-by-step explanation:

1 Convert 4\frac{3}{5}4

​5

​

​3

​​  to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

​c

​

​b

​​ =

​c

​

​ac+b

​​ .

\frac{1}{-(\frac{4\times 5+3}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​4×5+3

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

2 Simplify  4\times 54×5  to  2020.

\frac{1}{-(\frac{20+3}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​20+3

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

3 Simplify  20+320+3  to  2323.

\frac{1}{-(\frac{23}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

4 Simplify  \frac{2}{6}

​6

​

​2

​​   to  \frac{1}{3}

​3

​

​1

​​ .

\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{2}{4})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​3

​

​1

​​ −

​4

​

​2

​​ )

5 Simplify  \frac{2}{4}

​4

​

​2

​​   to  \frac{1}{2}

​2

​

​1

​​ .

\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{1}{2})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​3

​

​1

​​ −

​2

​

​1

​​ )

6 Find the Least Common Denominator (LCD) of \frac{1}{3},\frac{1}{2}

​3

​

​1

​​ ,

​2

​

​1

​​ . In other words, find the Least Common Multiple (LCM) of 3,23,2.

LCD = 66

7 Make the denominators the same as the LCD.

-\frac{1\times 2}{3\times 2}-\frac{1\times 3}{2\times 3}−

​3×2

​

​1×2

​​ −

​2×3

​

​1×3

​​

8 Simplify. Denominators are now the same.

-\frac{2}{6}-\frac{3}{6}−

​6

​

​2

​​ −

​6

​

​3

​​

9 Join the denominators.

\frac{-2-3}{6}

​6

​

​−2−3

​​

10 Simplify  -\frac{1}{3}-\frac{1}{2}−

​3

​

​1

​​ −

​2

​

​1

​​   to  -\frac{5}{6}−

​6

​

​5

​​ .

\frac{1}{-(\frac{23}{5})}\times \frac{-5}{6}

​−(

​5

​

​23

​​ )

​

​1

​​ ×

​6

​

​−5

​​

11 Move the negative sign to the left.

-\frac{1}{\frac{23}{5}}\times \frac{-5}{6}−

​

​5

​

​23

​​

​

​1

​​ ×

​6

​

​−5

​​

12 Invert and multiply.

-\frac{5}{23}\times \frac{-5}{6}−

​23

​

​5

​​ ×

​6

​

​−5

​​

13 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

​b

​

​a

​​ ×

​d

​

​c

​​ =

​bd

​

​ac

​​ .

-\frac{5\times -5}{23\times 6}−

​23×6

​

​5×−5

​​

14 Simplify  5\times -55×−5  to  -25−25.

-\frac{-25}{23\times 6}−

​23×6

​

​−25

​​

15 Simplify  23\times 623×6  to  138138.

-\frac{-25}{138}−

​138

​

​−25

​​

16 Move the negative sign to the left.

-(-\frac{25}{138})−(−

​138

​

​25

​​ )

17 Remove parentheses.

\frac{25}{138}

​138

​

​25

​​

7 0
2 years ago
Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha
Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

a = 20 --- tree distance from north gate

b =14 --- movement from south gate

c = 1775 --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

\triangle ADE \sim \triangle ACB --- similar triangles

So, we have the following equivalent ratios

AE:DE = AB:CB

Where:

AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775

Substitute these in the above equation

20:x/2 = 20 + x + 14: 1775

20:x/2 = x + 34: 1775

Express as fraction

\frac{20}{x/2} = \frac{x + 34}{1775}

\frac{40}{x} = \frac{x + 34}{1775}

Cross multiply

x *(x + 34) = 1775 * 40

Open bracket

x^2 + 34x = 71000

Rewrite as:

x^2 + 34x - 71000 = 0

Expand

x^2 + 284x -250x - 71000 = 0

Factorize

x(x + 284) -250(x + 284)= 0

Factor out x + 284

(x - 250)(x + 284)= 0

Split

x - 250 = 0 \ or\ x + 284= 0

Solve for x

x = 250 \ or\ x =- 284

x can't be negative;

So:

x = 250

6 0
3 years ago
About how many times faster does a bee flap its wings than a hummingbird?
aleksandrvk [35]

Answer:

a humming bird flpas its wings 80bps and a bee flaps its wings about 230bps

Step-by-step explanation:

3 0
3 years ago
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