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3 years ago

1

Mathematics

1 answer:

devlian [24]3 years ago

5 0

Answer:

-1

Step-by-step explanation:

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Draw segment EF so that is bisects RS. Mark their intersection appoint A

Neko [114]

Step-by-step explanation:

EF is a segment so it's a line with the end points as E and F. Line RS bisects(cuts in half) line EF. Then where the two lines meet is where A is.

Hope this helped.

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3 years ago

Find the volume of a CUBE if its side length is : x+2 in polynomial form

goldfiish [28.3K]

Volume = Length x Length x Length

Volume :

(x + 2) (x + 2) (x + 2)

= (x² + 4x + 4)(x + 2)

= x³ + 2x² + 4x² + 8x + 4x + 8

= x³ + 6x² + 12x + 8

Answer: x³ + 6x² + 12x + 8

8 0

3 years ago

Factor completely 81x8 − 1. (9x4 − 1)(9x4 1) (3x2 − 1)(3x2 1)(9x4 − 1) (3x2 − 1)(3x2 1)(9x4 1) (3x2 − 1)(3x2 1)(3x2 1)(3x2 1).

mojhsa [17]

Answer:

(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

Step-by-step explanation:

Using the identity for the difference of 2 squares;

a^2 - b^2 = (a - b)(a + b)

we put a^2 = 81x^8 and b^2 = 1 giving

a = 9x^4 and b = 1, so:

81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)

Applying the difference of 2 squares to 9x^4 - 1:

= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

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2 years ago

Solve for x. 79 (8x - 4) 3 -(3x + 17)

Liono4ka [1.6K]

Answer:

-2.4

Step-by-step explanation:

maybe... i am 99.99% sure

6 0

2 years ago

What binomial do you have to add to the polynomial:

marshall27 [118]

Answer:

a) $-2x^2+5xy$

b) $-3y^2+5xy$

Step-by-step explanation:

Part (a)

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

$-2x^2+5xy$

$(2x^2+3y^2-5xy+1)+(-2x^2+5xy)$

$=2x^2+3y^2-5xy+1-2x^2+5xy$

$=2x^2-2x^2+3y^2-5xy+5xy+1$

$=3y^2+1$

Part (b)

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

$-3y^2+5xy$

$(2x^2+3y^2-5xy+1)+(-3y^2+5xy)$

$=2x^2+3y^2-5xy+1-3y^2+5xy$

$=2x^2+3y^2-3y^2-5xy+5xy+1$

$=2x^2+1$

7 0

2 years ago