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jeka94
3 years ago
5

There are 8 triangles and 2 circles. What is the simplest ratio of circles to triangles?

Mathematics
2 answers:
Alchen [17]3 years ago
8 0

Answer:

1/4

Step-by-step explanation:

Ratio of circle to the triangle=2/8

=1/4

So 1/4 is the answer

Lilit [14]3 years ago
7 0

Answer:

Step-by-step explanation:

5:2

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If something starts out costing $500, and then is marked down by 25% on each of three separate occasions,what is the final price
astra-53 [7]
First markdown:  0.75($500) = $375
Second markdown:  0.75($375) = $281.25
Third markdown:     0.75($281.25) = $210.94
3 0
3 years ago
Please help right now!!!!! Solve the system of equations below. x + y = 7 2x + 3y = 16
motikmotik

Answer:

x=5 and y=2.

Step-by-step explanation:

We have been given a system of equations. We are asked to solve our given system.

x+y=7...(1)

2x+3y=16...(2)

From equation (1), we will get:

x=7-y

Upon substituting this value in equation (2), we will get:

2(7-y)+3y=16

14-2y+3y=16

14+y=16

14-14+y=16-14

y=2

Now, we will substitute y=2 in equation (1).

x+2=7

x+2-2=7-2

x=5

Therefore, the point (5,2) is solution for our given equation.

7 0
3 years ago
10 in<br> 8 in<br> 3 in<br> 12 in<br> Volume =
professor190 [17]

Answer:

Your data is not accurate...

4 0
3 years ago
The expression 3/4×1/2 represents a fraction of a circle that is shaded. Which diagram shows the correct shading?
sergiy2304 [10]
Hello,

Here is your answer:

The proper answer to this question is option D.

Here is how:

First solve the equation:

3*1=3
4*2=8

Which means your answer is D.

If you need anymore help feel free to ask me!

Hope this helps!
4 0
3 years ago
Read 2 more answers
The volume
Sedaia [141]
\bf \begin{array}{cccccclllll}&#10;\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\&#10;\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\&#10;y&=&{{ k}}&\cdot&x&#10;&&  y={{ k }}x&#10;\end{array}\\ \quad \\&#10;

and also

\bf \begin{array}{llllll}&#10;\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\&#10;\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\&#10;y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}&#10;&&y=\cfrac{{{  k}}}{x}&#10;\end{array}&#10;

now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad &#10;\begin{cases}&#10;V=42\\&#10;T=84\\&#10;P=8&#10;\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k&#10;\\\\\\&#10;V=\cfrac{4T}{P}\qquad now\quad &#10;\begin{cases}&#10;V=74\\&#10;P=10&#10;\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T
7 0
3 years ago
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