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Paraphin [41]
3 years ago
15

the morning shift at the point grocery store is about 6.5 hours long. if the cashiers make $10.25 an hour, how much do they make

each shift?
Mathematics
2 answers:
Verdich [7]3 years ago
7 0

Answer:

ganan aproximadamente $66 por  hora

Step-by-step explanation:

6.5*10.25= 66.625

Burka [1]3 years ago
6 0

Answer:

$66.63

Step-by-step explanation:

6.5 * 10.25 = 66.625 = 66.63

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Deva bought 9 1/2 m of cloth for rupees 28 1/2.Samruth buys 26 1/3 m of same cloth. how much should samruth pay the shopkeeper?
likoan [24]

For this case we can make the following rule of three:

9 1/2 m --------------> 28 1/2 rupees

26 1/3 m -------------> x

From here, we clear the value of x.

We have then:

x = (\frac{26+\frac{1}{3}}{9+\frac{1}{2}}) (28+\frac{1}{2})

Rewriting we have:

x = (\frac{\frac{79}{3}}{\frac{19}{2}}) (\frac{57}{2})

x = (\frac{158}{57}) (\frac{57}{2})

x = \frac{158}{2}

x = 79

Answer:

samruth should pay 79 rupees to the shopkeeper

5 0
3 years ago
Sketch the quadratic function ƒ(x) with a vertex at (–1, 2) and the points (0, 0) and (–2, 0). Which statement describes the par
Andrei [34K]

Answer:

Use this Formula m= y2 - y1 / x2-x2

Than find rise and run and graph it

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Could somebody solve this
Gre4nikov [31]
E^-3
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7 0
3 years ago
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What is the factored form of the expression 9x2 + 6x + 1?
DanielleElmas [232]

Answer:

(3x + 1)²

Step-by-step explanation:

Given

9x² + 6x + 1 ← is a perfect square of the form

(ax + b)² = a²x² + 2abx +  b²

Compare like terms to find a and b

a²x² = 9x² ⇒ a² = 9 ⇒ a = \sqrt{9} = 3

b² = 1 ⇒ b = \sqrt{1} = 1

and 2ab = 2 × 3 × 1 = 6

Thus

9x² + 6x + 1 = (3x + 1)²

4 0
3 years ago
Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.
avanturin [10]
In spherical coordinates, we have

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}

which gives volume element

\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta

and so the triple integral is given by

\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV
=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta
=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi
=\dfrac{592\pi}{15}
4 0
3 years ago
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