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Zielflug [23.3K]
2 years ago
13

Answer asap please??

Mathematics
1 answer:
natali 33 [55]2 years ago
7 0
Its c btw have a good way
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Given r= 10 and e=0.57, find the Cartesian coordinates. Check your answer.
Rudik [331]
I think it is d not sure tho
3 0
3 years ago
Solve for c: c - 12 = 3
vlabodo [156]

Steps to solve:

c - 12 = 3

~Add 12 to both sides

c = 15

Best of Luck!

8 0
3 years ago
Read 2 more answers
Helen wrote the following facts to try to show that division by 0 results in 0. Explain her error.
earnstyle [38]

Helen should of put 0 first, because if you're gonna divide, you need to put the product first, then one of the factoes.

So instead it should be 0÷(-7)=0

3 0
3 years ago
Pls answer and thanks!!
Keith_Richards [23]

Answer:

Problem:

Solve 3x−y=6;y=x−4

Steps:

I will try to solve your system of equations.

y=x−4;3x−y=6

Step: Solvey=x−4for y:

Step: Substitutex−4foryin3x−y=6:

3x−y=6

3x−(x−4)=6

2x+4=6(Simplify both sides of the equation)

2x+4+−4=6+−4(Add -4 to both sides)

2x=2

2x

2

=

2

2

(Divide both sides by 2)

x=1

Step: Substitute1forxiny=x−4:

y=x−4

y=1−4

y=−3(Simplify both sides of the equation)

Answer:

y=−3 and x=1

Step-by-step explanation:

Hope this helped you

3 0
2 years ago
Read 2 more answers
X-y=6<br> 2x-3z=16<br> 2y+z=4<br><br> Solve the systems of equations.
Neko [114]

Answer:

Given System of equation:

x-y =6                                  .....,[1]

2x-3z = 16                           ......[2]  

2y+z = 4                              .......[3]

Rewrite the equation [1] as

y = x - 6                                .......[4]

Substitute the value of [4] in [3], we get

2(x-6)+z = 4

Using distributive property on LHS ( i.e,  a \cdot (b+c) =a \cdot b+ b \cdot c )

then, we have

2x - 12 +z =4

Add 12 to both sides of an equation:

2x-12+z+12=4+12

Simplify:

2x +z = 16                         .......[5]

On substituting equation [2] in [5] we get;

2x+z=2x -3z

or

z = -3z

Add 3z both sides of an equation:

z+3z = -3z+3z

4z = 0

Simplify:

z = 0

Substitute the value of z = 0 in [2] to solve for x;

2x-3(0) = 16

or

2x = 16

Divide by 2 both sides of an equation:

\frac{2x}{2} =\frac{16}{2}

Simplify:

x= 8

Substitute the value of x =8 in equation [4] to solve for y;

y = 8-6 = 2

or

y = 2

Therefore, the solution for the given system of equation is;  x = 8 , y = 2 and z =0

5 0
3 years ago
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