I think it is d not sure tho
Helen should of put 0 first, because if you're gonna divide, you need to put the product first, then one of the factoes.
So instead it should be 0÷(-7)=0
Answer:
Problem:
Solve 3x−y=6;y=x−4
Steps:
I will try to solve your system of equations.
y=x−4;3x−y=6
Step: Solvey=x−4for y:
Step: Substitutex−4foryin3x−y=6:
3x−y=6
3x−(x−4)=6
2x+4=6(Simplify both sides of the equation)
2x+4+−4=6+−4(Add -4 to both sides)
2x=2
2x
2
=
2
2
(Divide both sides by 2)
x=1
Step: Substitute1forxiny=x−4:
y=x−4
y=1−4
y=−3(Simplify both sides of the equation)
Answer:
y=−3 and x=1
Step-by-step explanation:
Hope this helped you
Answer:
Given System of equation:
x-y =6 .....,[1]
2x-3z = 16 ......[2]
2y+z = 4 .......[3]
Rewrite the equation [1] as
y = x - 6 .......[4]
Substitute the value of [4] in [3], we get

Using distributive property on LHS ( i.e,
)
then, we have
2x - 12 +z =4
Add 12 to both sides of an equation:
2x-12+z+12=4+12
Simplify:
2x +z = 16 .......[5]
On substituting equation [2] in [5] we get;
2x+z=2x -3z
or
z = -3z
Add 3z both sides of an equation:
z+3z = -3z+3z
4z = 0
Simplify:
z = 0
Substitute the value of z = 0 in [2] to solve for x;

or
2x = 16
Divide by 2 both sides of an equation:

Simplify:
x= 8
Substitute the value of x =8 in equation [4] to solve for y;
y = 8-6 = 2
or
y = 2
Therefore, the solution for the given system of equation is; x = 8 , y = 2 and z =0