The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
From the question,
We are to factorize the expression (h+2k)²+4k²-h² completely
The expression can be factorized as shown below
(h+2k)²+4k²-h² becomes
(h+2k)² + 2²k²-h²
(h+2k)² + (2k)²-h²
Using difference of two squares
The expression (2k)²-h² = (2k+h)(2k-h)
Then,
(h+2k)² + (2k)²-h² becomes
(h+2k)² + (2k +h)(2k-h)
This can be written as
(h+2k)² + (h +2k)(2k-h)
Now,
Factorizing, we get
(h +2k)[(h+2k) + (2k-h)]
Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
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Answer:
1/2
Step-by-step explanation:
5/10 houses gave her chocolate
if you simplify 5/10 by dividing by both the top and bottom by 5 to get 1/2
Midpoint formula is M=( (x1+x²)/2 , (y1+y²)/2 )
let A be there point (x1,y1), our (2,3)
plug into the formula to get
(-2,1)=( (2+x²)/2, (3+y2)/2 )
so -2=(2+x2)/2 and 1=(3+y2)/2
x2=-6 and y2=-1
answer is B
I would be B. because from 4 to 20 is times 5 so you just divide 45 by 5 and you get 9.
HOPE THIS HELPS!!
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If (a, b) is on the graph of a function f(x), then (b, a) is on the graph of the inverse.
We have points on the graph of a function: {(-3, 9), (-1, 1), (0, 0), (2, 4)}.
The points on the graph of the inverse: {(9, -3), (1, -1), (0, 0), (4, 2)}.
<h3>Answer: (4, 2), (0, 0), (1, -1).</h3>