Before isolating s we need to simplify the equation using order of operations.
.7(3s+4)-1.1s = 7.9 -------> First distribute the .7
2.1s + 2.8 - 1.1s = 7.9 ------> Now combine like terms
s + 2.8 = 7.9 ------> Now to isolate s by subtracting 2.8 from both sides!
s = 7.9 - 2.8
s = 5.1
Answer:
15
Explanation:
In order to multiply, put a 1 under 12 (12/1)
Multiply straight across
5 x 12/4 x 1
60/4 (simplify it)
and boom! 15/1 or 15
Answer:
About $0.36 per ounce
Step-by-step explanation:
for problem 6, you will want to subtract both sides by 5.
n^2 + 7n + 10 = 0
then factor:
(n + 5) (n + 2) = 0
n+ 5 = 0, n +2 = 0
n = -5, n = -2
----------------------------
for problem 7, add - 12 and - 6 together
n^2 + 3n - 18
<em>(you can put </em>= 0 <em>next to the equation since that can make it easier to solve, I guess)</em>
n^2 + 3n - 18 = 0
then factor:
(n + 6) (n - 3) = 0
n + 6 = 0, n - 3 = 0
n = -6, n = 3
Answer:
The change in the car's distance is 8 feet
Step-by-step explanation:
* Lets explain how to solve the problem
- A car is driving away from a crosswalk
- The distance d (in feet) of the car from the crosswalk t seconds
since the car started moving is given by the formula d = t² + 3.5
- The time increasing from 1 second to 3 seconds
- We need to now the change of the car's distance from the crosswalk
∵ The equation of the distance is d = t² + 3.5
∵ The time is 1 second
∴ d = (1)² + 3.5
∴ d = 1 + 3.5 = 4.5 feet
∵ The time is 3 seconds
∴ d = (3)² + 3.5
∴ d = 9 + 3.5 = 12.5 feet
∵ The change of the distance = d of 3 sec - d of 1 sec
∵ d of 3 sec = 12.5 feet
∵ d of 1 sec = 4.5 feet
∴ The change of the distance = 12.5 - 4.5 = 8 feet
∴ The change in the car's distance is 8 feet
