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lorasvet [3.4K]
3 years ago
10

If milk cost $0.58 per pound how much would 3 and 1/2 gallon cost

Mathematics
2 answers:
SashulF [63]3 years ago
4 0

Answer:

$2.03

Step-by-step explanation:

What I did was I took .58 and times it by 3.5 to get the answer $2.03.

notka56 [123]3 years ago
4 0

Answer:

$17.46

Step-by-step explanation:

To find the Answer first find how many pounds are in 3.5 gallons.

In one gallon there are 8.6 pounds of milk, according to a quick google search.

Next multiply 8.6 pounds by 3.5 gallons

8.6*3.5= 30.1 pounds

Then multiply 30.1 pounds by $0.58

30.1 * $0.58= $17.45800

Now we round to the nearest hundredth

$17.45800≈ $17.46

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Step-by-step explanation:

Step 1:

We must calculate the area of the entire shape to determine the minimum BTU's required to cool the room effectively.

It is made up of a semi-circle a rectangle, and a trapezoid.

Step 2:

The area of a semi-circle =\frac{ \pi r^{2} }{2} .

Here, the diameter is 20 feet so the radius is 10 feet.

The area of the semi-circle =\frac{ \pi r^{2} }{2} =\frac{ (\pi) (10^{2}) }{2} = 157.079 square feet.

The area of a rectangle = (l)(w).

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The area of a rectangle = (l)(w) =(22)(20) = 440 square feet.

The area of a trapezoid =\frac{a+b}{2} (h).

Here a=12, b= 20, h= 3.

The area of a trapezoid =\frac{12+20}{2} (3) = 48 square feet.

Step 3:

The total area of the floor plan =157.079+440+48 = 645.079 square feet.

If 20 BTU's are required for a single square foot,

The number of BTU's for 645.079 square feet = (645.079)(20)=12,901.58 BTU's.

Rounding this off, we get 12,900 BTU's required  to cool the room effectively.

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Answer:

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Step-by-step explanation:

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