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olchik [2.2K]
3 years ago
5

Pls help ASAP it’s confusing and I’m short on time

Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

6(3x + 1/2)

9(2x + 1/3)

2(9x + 5) - 7

Step-by-step explanation:

6(3x + 1/2)= 18x + 3 ✅

9(2x + 1/3)= 18x + 3 ✅

4(4x + 1) -1= 16x + 3

2(9x + 5) - 7= 18x + 3 ✅

3(6x + 2) + 3= 18x + 9

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Tshshjnmdmsmmjnnnnbbbbbbnnnxnxjmkskkmfkdkd
JulsSmile [24]

Answer:

correct.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which function has real zeros at x= -2 and x=5?
hammer [34]

x = -2, x = 5

=> f(x) = a(x+2)(x-5),  a ∈ R

3 0
3 years ago
What is the value of the expression below when y 8 and z = 8? 9y + 3z​
aleksley [76]

Answer:

96

Step-by-step explanation:

8y+3z

9(8)+3(8)

72+24

96

6 0
3 years ago
I need help with someone explaining how to find the range of this! This course didn’t explain anything!
zaharov [31]

Answer:

(-infinity,3), D

Step-by-step explanation:

3 if x is greater than or equal to 1 is nothing. That leaves us with h(x)=2x+1 if x<1. If you substitute in 1 for x, you get 3, but of course that isn't possible, so the range is (-infinity,3), which is D.

4 0
3 years ago
Find the coordinates for the midpoint of the segment with endpoints give (3,5) and (-2,0)
Leto [7]

Answer:

The coordinates of the mid-point are :

(\frac{1}{2}, \frac{5}{2})

Step-by-step explanation:

We know that, the coordinates of the mid-point (<em>x</em>, <em>y</em>) of a line segment joining the points (<em>x</em>₁, <em>y</em>₁) and (<em>x</em>₂, <em>y</em>₂) is given by

(x, y) = (\frac{x_{1} +x_{2} }{2},\frac{y_{1}+y_{2} }{2} )

Now, we have the given points as (3, 5) and (-2, 0).

By using the above formula, coordinates of the mid-point (<em>x</em>, <em>y</em>) of the line-segment joining the points (3, 5) and (-2, 0) is given by,

x = \frac{3+(-2)}{2} = \frac{3-2}{2} = \frac{1}{2}

y = \frac{5+0}{2} = \frac{5}{2}

∴ coordinates of the mid-point of the line-segment joining the points (3,5) and (-2,0) is (\frac{1}{2}, \frac{5}{2}).

8 0
3 years ago
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