2(a+3)+3(2a-1)
=2a+6+6a-3
=8a+3
        
             
        
        
        
What question do u need help with?
        
             
        
        
        
To split this trinomial into two binomials, let's try and find two numbers which add to 6 and multiply to 8. To do this, we can list all the factors of 8 and then choose which factors also add to 6.
Factors of 8: (1, 8), (2, 4)
1 + 8 = 9, meaning that 1 and 8 are not the factors we are looking for. However, 2 and 4 do add to 6. By combining these numbers which an x (so that we can produce the  term at the front of the trinomial), we find the binomials:
 term at the front of the trinomial), we find the binomials:
 and
 and 
The answer is x + 2 and x + 4.
 
        
                    
             
        
        
        
Answer:
Sorry it's acually (h+3)(h-9)
 
        
             
        
        
        
You would plug in 4 for x.
f(4)= (4) - 6 = -2