the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
You add 11y to 11y and 12x to 12x. then you have 17=22y+ 24x=14
-14 -14
14 cancels out. 3=22y+24x
Suppose you wanted to calculate the geometric mean of the numbers 2 and 32. This simple example can be done in your head. First, take the product; 2 times 32 is 64. Because there are only two numbers, the nth root is the square root, and the square root of 64 is 8.
The prime factorization of 15 is 1 * 3 * 5
Answer:
Step-by-step explanation:
