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Angelina_Jolie [31]

3 years ago

12

Gary Foshee created a popular probability puzzle that goes like this: "I have two children. One is a boy born on a Tuesday. What

1 answer:

GrogVix [38]3 years ago

8 0

Answer:

wendsday and thursaday

Step-by-step explanation:

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What is the value of tan A? (will mark brainliest and give thanks!)

Elena L [17]

The best answer is 15/8 and it could be simplified I think

5 0

3 years ago

A scientist makes an acid solution by adding drops of acid to 1.2 L of water. The final volume of the acid solution is 1.202 L.

laila [671]

Answer:

40 drops

Approximately 0.166 %

Step-by-step explanation:

It would be easier to work the same units for volume

Since there are 1000 ml in a liter

Original water volume 1.2 L = 1.2 x 1000 = 1200 mLl

The final volume of the acid-water solution = 1.202 L = 1202 mL

So total volume of acid added = 1202-1200 = 2 mL

Each drop of acid is 0.05 mL

Number of drops added = 2/.05 = 40 drops

Percent of acid in acid solution = (Volume of acid added)/(Final volume) x 100 = (2/1202) ≈ 0.00166 x 100 ≈ 0.166 %

7 0

2 years ago

The sum of two numbers is 18. The larger number is twice as large as the smaller number. What are the two numbers? Please explai

snow_tiger [21]

The two numbers are 12 and 16. 12 + 6 = 18. 6 doubled is 12. 12 plus 6 equals 18.

7 0

3 years ago

Need help with image below

Ann [662]

Step-by-step explanation:

please provide formula

7 0

3 years ago

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

3 years ago