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eduard
3 years ago
5

A high jumper starts the bar at 48 inches and raises the bar 1/2 inch after each jump.How high will the bar be after the seventh

seventh jump?
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer:

51.5 in , Formula: y=1/2x+48

Step-by-step explanation:

First, create a formula as shown above

Next, plug your number into the formula:

y=1/2(7)+48

Then, simplify your equation by multiplying 1/2 by 7 and getting 3.5, now add 48 and you get 51.5in

Last, check your work by adding 1/2 seven times and you will get the same result

I hope this helps you and if it does please give a thanks (i would eternally appreciate a brainliest trying t level up)

If i am wrong leave a comment

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Step-by-step explanation:

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In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
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Answer:

(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743

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Step-by-step explanation:

For this problem we have the following data given:

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\bar X_2 = 8 represent the sample mean for the other department

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n_2 = 20 represent the sample size for the second group

s_1 = 2 represent the deviation for the first group

s_2 =1 represent the deviation for the second group

Confidence interval

The confidence interval for the difference in the true means is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

The confidence given is 95% or 9.5, then the significance level is \alpha=0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

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And replacing we got:

(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743

(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926

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