You say that there is uniform acceleration so:
vf-vi=at (final velocity minus initial velocity is equal to acceleration times time)
We know vf, vi, and t so we can solve for acceleration:
24-12=a10
12=10a
a=1.2
That is the acceleration, we will need to integrate with respect to time twice...
v=⌠a dt
v=at+vi , we know a=1.2m/s^2 and vi=12m/s
v=1.2t+12,
x=⌠1.2t+12 dt
x=1.2t^2/2+12t+xo, we can just let xo=0 for this problem...
x(t)=0.6t^2+12t
Now we know that this acceleration lasts for 10 seconds so the distance traveled in that time is:
x(10)=0.6(10^2)+12(10)
x(10)=60+120
x(10)=180 meters
Answer:
Yeah
Step-by-step explanation:
Answer: There's no answer choices but the exact value is -3±2√5
Step-by-step explanation:
Given:
The length of a string in yards is a function f(n) of the length n in inches
To find:
The function rule for the given situation.
Solution:
We know that,
12 inches = 1 yard
1 inch = 
yard
n inches = 
yards
It is given that the length of a string in yards is a function f(n) of the length n in inches. So,
Therefore, the required function for the given situation is .
Answer:
x = 0
y = 2
Step-by-step explanation:
3x + 9y = 18 ---------eqn 1
y = x + 2---------eqn 2
Substitute eqn 2 into eqn 1, for the value of y
3x + 9( x + 2) = 18
3x + 9x + 18 = 18
12x + 18 = 18
12x = 18 -18
12x = 0
Divide both sides by 12 , to get the value of x.
12x/ 12 = 0/12
x = 0
Substitute x = 0 into eqn 2
y = x + 2
y = 0 +2
y = 2
Hint: to confirm the values
x = 0
y = 2
Let's take eqn 1 ,
3x + 9y = 18
3(0) + 9(2)
= 0 + 18
= 18
Correct
Let's take eqn 2
y = x + 2
Let's find y
y = 0 + 2
y = 2
Correct too
