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2 years ago

What is the written form of the decimal number .954

Mathematics

2 answers:

Naddika [18.5K]2 years ago

6 0

Nine hundred and fifty four thousandth, i believe

11Alexandr11 [23.1K]2 years ago

5 0

The written form of 0.954 is nine hundred and fifty four thousandths.
There is a th at the end of thousandths to signify that the number is in decimals and not a whole number.

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Q2) If z is directly proportional to x and z = 12 when x = 3, find the value of x when z = 18.

LenKa [72]

Answer:

4.5

Step-by-step explanation:

→ Set up the direct proportion equation

z = kx

→ Substitute in the values

12 = 3k

→ Divide both sides by 3 to isolate k

4 = k

→ Substitute the value of k back into the original direct proportion equation

z = 4x

→ Substitute the value of z in

18 = 4x

→ Divide both sides by 4 to isolate x

4.5 = x

4 0

3 years ago

Read 2 more answers

You have a large jar that initially contains 30 red marbles and 20 blue marbles. We also have a large supply of extra marbles of

Dima020 [189]

Answer:

There is a 57.68% probability that this last marble is red.

There is a 20.78% probability that we actually drew the same marble all four times.

Step-by-step explanation:

Initially, there are 50 marbles, of which:

30 are red

20 are blue

Any time a red marble is drawn:

The marble is placed back, and another three red marbles are added

Any time a blue marble is drawn

The marble is placed back, and another five blue marbles are added.

The first three marbles can have the following combinations:

R - R - R

R - R - B

R - B - R

R - B - B

B - R - R

B - R - B

B - B - R

B - B - B

Now, for each case, we have to find the probability that the last marble is red. So

$P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8}$

$P_{1}$ is the probability that we go R - R - R - R

There are 50 marbles, of which 30 are red. So, the probability of the first marble sorted being red is $\frac{30}{50} = \frac{3}{5}$ .

Now the red marble is returned to the bag, and another 3 red marbles are added.

Now there are 53 marbles, of which 33 are red. So, when the first marble sorted is red, the probability that the second is also red is $\frac{33}{53}$

Again, the red marble is returned to the bag, and another 3 red marbles are added

Now there are 56 marbles, of which 36 are red. So, in this sequence, the probability of the third marble sorted being red is $\frac{36}{56}$

Again, the red marble sorted is returned, and another 3 are added.

Now there are 59 marbles, of which 39 are red. So, in this sequence, the probability of the fourth marble sorted being red is $\frac{39}{59}$ . So

$P_{1} = \frac{3}{5}*\frac{33}{53}*\frac{36}{56}*\frac{39}{59} = \frac{138996}{875560} = 0.1588$

$P_{2}$ is the probability that we go R - R - B - R

$P_{2} = \frac{3}{5}*\frac{33}{53}*\frac{20}{56}*\frac{36}{61} = \frac{71280}{905240} = 0.0788$

$P_{3}$ is the probability that we go R - B - R - R

$P_{3} = \frac{3}{5}*\frac{20}{53}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{937570} = 0.076$

$P_{4}$ is the probability that we go R - B - B - R

$P_{4} = \frac{3}{5}*\frac{20}{53}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{968310} = 0.0511$

$P_{5}$ is the probability that we go B - R - R - R

$P_{5} = \frac{2}{5}*\frac{30}{55}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{972950} = 0.0733$

$P_{6}$ is the probability that we go B - R - B - R

$P_{6} = \frac{2}{5}*\frac{30}{55}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{1004850} = 0.0493$

$P_{7}$ is the probability that we go B - B - R - R

$P_{7} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{33}{63} = \frac{825}{17325} = 0.0476$

$P_{8}$ is the probability that we go B - B - B - R

$P_{8} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{30}{65} = \frac{750}{17875} = 0.0419$

So, the probability that this last marble is red is:

$P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8} = 0.1588 + 0.0788 + 0.076 + 0.0511 + 0.0733 + 0.0493 + 0.0476 + 0.0419 = 0.5768$

There is a 57.68% probability that this last marble is red.

What's the probability that we actually drew the same marble all four times?

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that we go R-R-R-R. It is the same $P_{1}$ from the previous item(the last marble being red). So $P_{1} = 0.1588$

$P_{2}$ is the probability that we go B-B-B-B. It is almost the same as $P_{8}$ in the previous exercise. The lone difference is that for the last marble we want it to be blue. There are 65 marbles, 35 of which are blue.

$P_{2} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{35}{65} = \frac{875}{17875} = 0.0490$

$P = P_{1} + P_{2} = 0.1588 + 0.0490 = 0.2078$

There is a 20.78% probability that we actually drew the same marble all four times

3 0

2 years ago

Provide in simplest form <br> 12% of 40

AnnZ [28]

To get 10% of 40, you move the decimal point one way to the left. So 10% of 40 is 4
Now you need 2% and because you know 10% is 4, you divide that by 10 and multiply it by 2 because of the 2%
4/10=.4 .4•2=.8
Now you add them
4+.8=4.8
12% of 40 is 4.8

7 0

3 years ago

CAN SOMEONE PLEASE HELP ME PLEASE PLEASE!!!

Galina-37 [17]

Step-by-step explanation:

this is really simple : we only need to put the given x and y coordinate values into both equations and see, if both equations remain true.

(-2, -1) means x = -2, y = -1

first equation :

-1 = 3×-2 + 5 = -6 + 5 = -1

so, -1 = -1

true.

second equation :

-2 + -1 = -3

-3 = -3

true.

therefore, (-2, -1) is a solution to the linear system.

the point is the crossing point of both lines.

4 0

2 years ago

Nestlé water pumps 1.2 million gallons per day out of G. Springs to put in bottles.

Delicious77 [7]

Answer:

3.2×10⁷ liters/week

Step-by-step explanation:

$\dfrac{1.2\cdot 10^6\,gal}{1\,day}\cdot\dfrac{7\,day}{1\,week}\cdot\dfrac{8\,pint}{1\,gal}\cdot\dfrac{1\,L}{2.11\,pint}=\dfrac{1.2\cdot 10^6\cdot 7\cdot 8\,L}{2.11\,week}\\\\\approx 3.2\cdot 10^7\,\dfrac{L}{week}$

5 0

2 years ago

Read 2 more answers