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3 years ago

Find the slope from the given points (-5 , 3) (2 , 4)

Mathematics

1 answer:

STALIN [3.7K]3 years ago

6 0

Answer: 1/7

(-5,3)= (x1,y1)

(2,4)= (x2,y2)

Slope= $\frac{y2-y1}{x2-x1}$

= $\frac{4-3}{2-(-5)}$

= $\frac{1}{7}$

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Tim estimates that 60÷5.7 is about 10.Will the actual quotient be greater than 10 explain

Zepler [3.9K]

Well first you can do the problem. So take 60 divided by 5.7. When it is done it will come out to about 10.5263 which is a irrational number. So yes the quotient will be larger than 10.
Hope I helped!

8 0

3 years ago

2. Find the 20th term of an arithmetic sequence if its 6th term is 14 and 14th term is 6.

Fudgin [204]

Answer:

$\sf t_{20}= 0$

Step-by-step explanation:

<h3>Arithmetic sequence:</h3>

$\sf \boxed{\bf n^{th} \ term = a + (n-1)d}\\\\\text{Here, a is the first term ; d is the common difference }$

6th term is 14 ⇒ $\sf t_6 = 14$

a + (6 - 1)d = 14

a + 5d = 14 --------------(I)

14th term is 6 ⇒ $\sf t_{14} = 6$

a + (14-1)d = 6

a + 13d = 6 ----------------(II)

Subtract equation (II) from equation(I)

(I) a + 5d = 14

(II) a + 13d = 6

-8d = 8

d = 8 ÷(-8)

$\sf \boxed{\bf d= (-1)}$

Plugin d = -1 in equation (I)

a + 5(-1) = 14

a -5 = 14

a = 14 + 5

$\sf \boxed{\bf a = 19}$

20th term:

$\sf t_{20}= 19 + 19*(-1)$

= 19 - 19

$\sf \boxed{\bf t_{20} = 0}$

8 0

1 year ago

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Can you solve this please ;)

AleksAgata [21]

C) X is greater than or equal to 0

(Domain is all the x-values the line goes through)

3 0

3 years ago

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Find the area of a plane figure bounded by lines

natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6 ⇒ x² + x - 2 = 0 ⇒ (x + 2)(x - 1) = 0 ⇒ x = -2, x = 1

Now, integrate from x = -2 to x = 1

$\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,$ <em>the bottom of the integral is -2 </em>

= $\int\limits^1_2 {x+6-x^{2}-2x-4 } \,$

= $\int\limits^1_2 {-x^{2}-x+2 } \,$

= $\frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,$

= $(\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))$

= $(\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)$

= $\frac{-9}{3} + \frac{3}{2} +6$

= -3 + 1.5 + 6

= 4.5

3 0

3 years ago

"My friend here Justin, he's already taken, and he's cracked at Fornite my guy.

Galina-37 [17]

Answer:

i dk what to say

Step-by-step explanation:

5 0

2 years ago

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