I think that you round to 9.80 seconds. Pardon me, I didn't understand the problem well
Answer:
Width of the archway at its base: 11 units, height of the archway at its highest point: 30.25 units.
Step-by-step explanation:
The graph that represents the equation 
is now sketched with the help of a graphing tool and whose representation is included in a file attached below. The point associated with x-intercepts are (-3, 0) and (8, 0) and the point associated with the highest point is (2.5, 30.25). The width of the archway at its base (
) and the height of the archway at its highest point (
) are, respectively:
Width of the archway at its base: 11 units, height of the archway at its highest point: 30.25 units.
X+.75=12.25
X+.75-.75=12.25-.75
X=11.50
11.50 wasMarietta's wage before her raise
Answer: hey sup fellow player
Step-by-step explanation: how’s life eh?
Answer:
7.25cm
Step-by-step explanation:
Let the complete question be;
<em>Jill cuts a piece of cardboard in the shape of a trapezoid. The area of the is 43.5sp cm. If bases are 3.5cm and 8.5cm long, what is the height.</em>
<em />
Area of a trapezoid = 1/2(a+b)*h
a and b are the parallel sides (bases)
h is the height
Given
a = 3.5cm
b = 8.5cm
A = 43.5 sq.cm
Required
Height h
Substitute the given values into the expression
Area of a trapezoid = 1/2(a+b)*h
43.5 = 1/2(3.5+8.5)*h
43.5 = 1/2 * 12h
43.5 = 6h
h = 43.5/6
h = 7.25cm
Hence the height is 7.25cm
