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gregori [183]
3 years ago
11

you put $6,000 in an account the account of $1050 simple interest in 5 years was the annual interest rate​

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0

Ending Balance with Simple Interest Formula

This can be determined by multiplying the $1000 original balance times [1+(10%)(3)], or times 1.30. Instead of using this alternative formula, the amount earned could be simply added to the original balance to find the ending balance.Answer:

Step-by-step explanation:

here is your answer let me know if you got it right

please rate this in just say thank you

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If cosx=1/12 and sinx&gt;0 find tan2x
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cosx=\frac{1}{12}\\\\sin^2x+cos^2x=1\\\\sin^2x+\left(\frac{1}{12}\right)^2=1\\\\sin^2x+\frac{1}{144}=1\\\\sin^2x=1-\frac{1}{144}\\\\sin^2x=\frac{144}{144}-\frac{1}{144}\\\\sin^2x=\frac{143}{144}\\\\sinx=\sqrt\frac{143}{144}\\\\sinx=\frac{\sqrt{143}}{12}


tan2x=\frac{sin2x}{cos2x}\\\\sin2x=2sinxcosx;\ cos2x=cos^2x-sin^2x\\\\sin2x=2\cdot\frac{\sqrt{143}}{12}\cdot\frac{1}{12}=\frac{2\sqrt{143}}{144}\\\\cos2x=\left(\frac{1}{12}\right)^2-\left(\frac{\sqrt{143}}{12}\right)^2=\frac{1}{144}-\frac{143}{144}=-\frac{142}{144}\\\\tan2x=\frac{2\sqrt{143}}{144}:\left(-\frac{142}{144}\right)=-\frac{2\sqrt{143}}{144}\cdot\frac{144}{142}=-\frac{\sqrt{143}}{71}
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3 years ago
The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont
Kryger [21]

Answer:

a) P= $56,972.5

b) A=$1,26,792.3

Step-by-step explanation:

Given Data:

Interest rate=r= 0.08  per year

No. of years=t=10

Rate of continuous money flow is given by the function

f(t)=2000

a) to find the present value of money

P=\int\limits^n_0 {f(t)e^{-rt} } \, dt

Put f(t)=2000 and n=10 years and r=0.08

P=\int\limits^n_0 {2000e^{-0.08t} } \, dt

Now integrate

P= {2000(\frac{e^{-0.08t}}{-0.08} )

P= -\frac{2000}{0.08} (e^{-0.08*10}-e^{-0.08*0})

P= -\frac{2000}{0.08} (e^{-0.8}-e^{0})

P= -\frac{2000}{0.08} (0.4493-2.7282)

P= -\frac{2000}{0.08} (-2.2789)

P= -25000(-2.2789)

P= $56972.5

(b) to find the accumulated amount of money at t=10

A=P(e^{rt} )

Where P is the present worth already calculated in part a

A=56972.5(e^{0.08*10} )

A=56972.5(e^{0.8} )

A=56972.5(2.2255 )

A=$1,26,792.3

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3 years ago
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Ok so slope is y2-y1/x2-x1. the question is asking you to find the value of x1 that will make the slope 7. plug in your coordinates to get (7-(-7))/(4-s)=7, then you simplify to get 14/(4-s)=7, multiply both sides by (4-s) to get 14=7(4-s), divide both sides by 7 to get 2=4-s, and then solve to get that s=2. hope this helps!
3 0
3 years ago
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