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Dominik [7]
3 years ago
10

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0

Answer: 69.75 miles

<u>Step-by-step explanation:</u>

The explicit rule for an arithmetic sequence is: a_n=a_1+d(n-1)\ \text{where}\ a_1\ \text{is the first term and d is the difference}

In the given problem, a_1=1.75 and d = 0.25

a_n=1.75+0.25(n-1)\\.\quad=1.75+0.25n-0.25\\.\quad=0.25n+1.50\\\\a_{18}=0.25(18)+1.50\\.\quad=4.50+1.50\\.\quad=6.00

The sum of an arithmetic sequence is: S_n=\dfrac{a_1+a_n}{2}\cdot n

S_{18}=\dfrac{1.75+6}{2}\cdot 18\\\\.\quad=7.75\cdot 9\\\\.\quad=69.75

miskamm [114]3 years ago
3 0
Akim ran 69.75 miles in the course of 18 days.
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Answer:

$ 5,500

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3 years ago
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The functio p(x)= x(x-5)(x-2)(x+3) has four zeros. What is the smallest zero.
loris [4]

Answer:

x = 5 or x = 2 or x = 0 or x = -3 thus 0 is the smallest root

Step-by-step explanation:

Solve for x:

x (x - 5) (x - 2) (x + 3) = 0

Split into four equations:

x - 5 = 0 or x - 2 = 0 or x = 0 or x + 3 = 0

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x = 5 or x - 2 = 0 or x = 0 or x + 3 = 0

Add 2 to both sides:

x = 5 or x = 2 or x = 0 or x + 3 = 0

Subtract 3 from both sides:

Answer: x = 5 or x = 2 or x = 0 or x = -3

8 0
3 years ago
HEY CAN ANYONE HELP ME!
nataly862011 [7]

Answer:

Given: In triangle ABC and triangle DBE where DE is parallel to AC.

In ΔABC and ΔDBE

DE || AC   [Given]

As we know, a line that cuts across two or more parallel lines.  In the given figure, the line AB is a transversal.

Line segment  AB is transversal that intersects two parallel lines.  [Conclusion from statement 1.]

Corresponding angles theorem: two parallel lines are cut by a transversal, then the  corresponding angles are congruent.

then;

\angle BDE \cong \angle BAC  and

\angle BEC \cong \angle BCA

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.

by Reflexive property of equality:

\angle B \cong \angle B  

By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar

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\triangle ABC \sim \triangle DBE

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then, we have;

\frac{BD}{BA}                  [By definition of similar triangles]

therefore, the missing statement and the reasons are

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3.\angle BDE \cong \angle BAC      Corresponding angles theorem

and  \angle BEC \cong \angle BCA        

5. \triangle ABC \sim \triangle DBE   AAA similarity postulates    

6. BD over BA                                                    Definition of similar triangle



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Answer:

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3 0
3 years ago
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