3 years ago

Simplify the expressions. i^23

Mathematics

1 answer:

masha68 [24]3 years ago

8 0

Answer:

-i

Step-by-step explanation:

i^0=1

i^1=i

i^2=-1

i^3=-i

i^4=1

This repeats so we want to see how many 4 factors of i there is in i^(23) which is 5 with a remainder of 3.

So i^(23)=i^3=-i.

i^(23)=i^(5*4+3)=(i^4)^5 * (i^3)=(1)^5 * (-i)=1(-i)=-i.

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