All categories

3 years ago

I give private lessons in Brazil. I can exert this activity in the United States?

Mathematics

1 answer:

Mrac [35]3 years ago

7 0

Ummm speaking a different language

You might be interested in

18x-16y=-312 78x-16y=408

patriot [66]

That is system of equation.

8 0

2 years ago

Which of the following describes a rectangular prism?

Allushta [10]

Answer:

D. a shape with six faces where all six faces are identical

3 0

3 years ago

Read 2 more answers

Find the perimeter of the polygon. Round your answer to the nearest tenth.

lubasha [3.4K]

Answer:

Perimeter is 38.8 units and approximately 39 units

Step-by-step explanation:

Given: Graph

To find: perimeter of the polygon

Solution:

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

As per the graph,

point P is (-2,11)

point Q is (-4,6)

point R is (2,0)

point S is (1,7)

point T is (8,7)

$PQ=\sqrt{(-4+2)^2+(6-11)^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{29}=5.4\,\,units\\QR=\sqrt{(2+4)^2+(0-6)^2}=\sqrt{(6)^2+(-6)^2}=\sqrt{72}=8.5\,\,units\\RS=\sqrt{(1-2)^2+(7-0)^2}=\sqrt{(-1)^2+(7)^2}=\sqrt{50}=7.1\,\,units\\ST=\sqrt{(8-1)^2+(7-7)^2}=\sqrt{(7)^2+(0)^2}=\sqrt{49}=7\,\,units\\PT=\sqrt{(8+2)^2+(7-11)^2}=\sqrt{(10)^2+(-4)^2}=\sqrt{116}=10.8\,\,units$

Perimeter refers to sum of lengths of all the sides.

Perimeter = $5.4+8.5+7.1+7+10.8=38.8$

Or approximately 39 units

3 0

3 years ago

Tim plans to spend 40 hours on exercise training to earn a private trainer license. He has saved $2,000

grigory [225]

Answer:

round it then divide it by 5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The owner of a football team claims that the average attendance at games is over 523, and he is therefore justified in moving th

USPshnik [31]

Answer:

C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.

Step-by-step explanation:

Let μ be the the average attendance at games of the football team

The claim: the average attendance at games is over 523

Null and alternative hypotheses are:

$H_{0}$ : μ=523

$H_{a}$ : μ>523

The conclusion is failure to reject the null hypothesis.

This means that test statistic is lower than critical value. Therefore it is not significant, there is no significant evidence to accept the alternative hypothesis.

That is no significant evidence that the average attendance at games of the football team is greater than 523.

7 0

2 years ago