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allsm [11]
3 years ago
5

1-3(x-5)=5x-12/2 solve this equation​

Mathematics
2 answers:
Assoli18 [71]3 years ago
8 0

Answer and Step-by-step explanation:

The~answer~you~should~be~getting~is : x=\frac{11}{4}

Step 1: Simplify both sides of the equation:

1+(-3)(x)+(-3)(-5)=5x+-6   (Distribute)

1+-3x+15=5x+-6

(-3x)+(1+15)=5x-6  (Combine~the~like~terms)

-3x+16=5x-6

Step 2: Subtract 5x from both sides:

-3x+16=5x=5x-6-5x

-8x+16=-6

Step 3: Subtract 16 from both sides:

-8x+16-16=-6-16

-8x=-22

Step 4: Divide both sides by -8:

\frac{-8x}{-8} \frac{-22}{-8}

x=\frac{11}{4}

Answer is : x=\frac{11}{4}

7nadin3 [17]3 years ago
4 0

Answer:

x= 1/3

Step-by-step explanation:

simplify so you can isolate x quicker: 2x-5=5x-6

subtract 2x from both sides: -5=3x-6

add 6 to both sides: 1=3x

divide both side by the 3 to isolate x: 1/3=x

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1/12 plus 1/4 pleaseee
ser-zykov [4K]

Answer:

1/3

Step-by-step explanation:

1/4 is equal to 3/12. So then we add the 3/12 and the 1/12 and get 4/12. 4/12 is equal to 1/3, so that is our answer. Hope this helps!

4 0
3 years ago
Which statement is true
liberstina [14]
B is true
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8 0
3 years ago
165 is what percent of 433? set up a proportion and solve
seropon [69]

Answer:

38.1%

Step-by-step explanation:

Divide 165 by 433

165/433 = 0.381

Multiply the answer by 100

0.381 x 100 = 38.1

6 0
3 years ago
Last spring, the drama department at Greenwood High School had 10 student audition for the musical. This spring, there were 8 st
Brilliant_brown [7]
20% cuz 2/10 students dropout then 2/10=20%
5 0
3 years ago
Find the equation of the line that passes through (0, -3) and is parallel to
Tresset [83]

Hey there!

\\

  • Answer:

\green{\boxed{\red{\bold{\sf{y = \dfrac{7}{6}x - 3}}}}}

\\

  • Explanation:

To find the equation of a line, we first have to determine its slope knowing that parallel lines have the same slope.

Let the line that we are trying to determine its equation be \: \sf{d_1} \: and the line that is parallel to \: \sf{d_1} \: be \: \sf{d_2} \: .

\sf{d_2} \: passes through the points (9 , 2) and (3 , -5) which means that we can find its slope using the slope formula:

\sf{m = \dfrac{\Delta y}{\Delta x} = \dfrac{\green{y_2} - \orange{y_1}}{\red{x_2} - \blue{x_1 }}}

\\

⇒Subtitute the values :

\sf{(\overbrace{\blue{9}}^{\blue{x_1}}\: , \: \overbrace{\orange{2}}^{\orange{y_1}}) \: \: and \: \: (\overbrace{\red{3}}^{\red{x_2}} \: , \: \overbrace{\green{-5}}^{\green{y_2}} )}

\implies \sf{m = \dfrac{\Delta y}{\Delta x} = \dfrac{\green{-5} - \orange{2}}{\red{ \: \: 3} - \blue{9 }} = \dfrac{ - 7}{ - 6} = \boxed{ \bold{\dfrac{7}{6} }}}

\sf{\bold{The \: slope \: of \: both \: lines \: is \: \dfrac{7}{6}}}.

Assuming that we want to get the equation in Slope-Intercept Form, let's substitute m = 7/6:

Slope-Intercept Form:

\sf{y = mx + b} \\ \sf{Where \: m \: is \: the \: slope \: of \:  the \: line \: and \: b \: is \: the \: y-intercept.}

\implies \sf{y = \bold{\dfrac{7}{6}}x + b} \\

We know that the coordinates of the point (0 , -3) verify the equation since it is on the line \: \sf{d_1} \:. Now, replace y with -3 and x with 0:

\implies \sf{\overbrace{-3}^{y} = \dfrac{7}{8} \times \overbrace{0}^{x} + b} \\ \\ \implies \sf{-3 = 0 + b} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \sf{\boxed{\bold{b = -3}} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:

Therefore, the equation of the line \: \bold{d_1} \: is \green{\boxed{\red{\bold{\sf{y = \dfrac{7}{6}x - 3}}}}}

\\

▪️Learn more about finding the equation of a line that is parallel to another one here:

↣brainly.com/question/27497166

8 0
2 years ago
Read 2 more answers
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