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Alika [10]
3 years ago
11

Factor the expression 3x +9 The factored expression is.... ​

Mathematics
1 answer:
muminat3 years ago
5 0

Answer:

i believe it's "(x+3)(x+3)(x+3)" but double check me on that.

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Part A: Solve the equation 7x + 3x − 18 = 6(x + 3), and show your work. (5 points)
Serhud [2]

Answer:

exact form: 12/5

decimal form: 2.6

mixed number : 2 2/5

Step-by-step explanation:

3 0
3 years ago
Determine the intercepts of the line. yy y y -intercept: (\Big( ( left parenthesis ,, , comma )\Big) ) right parenthesis xx x x
BlackZzzverrR [31]

Question:

Give all the x and y intercept of the function

f(x) = \frac{3x^2 - 3x-60}{2x^3 + 2x^2-34x+30}

Answer:

The x intercepts are x = 5 and x = -4

The y intercept is at y = -2

Step-by-step explanation:

Factorizing the numerator of the expression we find the x intercepts as follows;

f(x) = \frac{3x^2 - 3x-60}{2x^3 + 2x^2-34x+30} =\frac{3(x-5)(x+4)}{2x^3 + 2x^2-34x+30}

Therefore, the x intercept are

x = 5 and x = -4

To find the y intercept, we put x = 0 to get y = -2

Therefore, the y intercept is at y = -2

Factorizing the denominator we find the values for which the equation is undefined

2·x³ + 2·x² - 34·x + 30 = 2·(x-1)·(x-3)·(x+5) which gives

x = 1, 3 and -5.

4 0
3 years ago
Calculate dy/dx if Ln (x + y) = ex/y
Margaret [11]
Assuming that the given expression is    ln(x+y)=  e^{x/y}

You calculate dy / dx = y' as:

  1
-------. y' = e^(x/y) * (-x/y^2)
x + y

=> y' = e^(x/y) * (-x/y^2) * (x + y).

Answer dy / dx = - e^(x/y) (x/y^2) (x+y)




3 0
3 years ago
If temperature is 4 degrees and falls by 6 degrees, what is the new temperature?
Step2247 [10]

Answer:

-2 degrees

Step-by-step explanation:

4-6=-2

so its -2 degrees.

Hope this helps :D

5 0
3 years ago
Read 2 more answers
Jimmy earned $8 for every pizza he delivers.
kumpel [21]

Answer:

The dependent variable is p, or number of pizzas delivered.

Explanation:

The amount of money he gets for every pizza delivered will not change, but the amount of pizzas delivered can change.

4 0
3 years ago
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