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Delvig [45]
2 years ago
9

Find the length of BC​

Mathematics
1 answer:
Likurg_2 [28]2 years ago
8 0

Answer:

BC = 88.88

Step-by-step explanation:

Comment.

This looks like an example of the cos law.

Givens

AB = 100 m

<A = 60 degrees

AC = 70 m

Cos(60) = 1/2

BC = ?

Formula

BC^2  = AB^2 + AC^2 - 2*AB*AC * Cos(60)

Solution

BC^2 = 100^2 + 70^2 - 2*100*70 * 1/2     1/2 and 2 cancel out

BC^2 = 10000 + 4900 - 7000      

BC^2 = 7900                                             Take the sqr root of both sides

√BC^2 = √7900

BC = 88.88

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The value of the length DF is 1/4 of that of CD because of the Angle Bisector Theorem for triangles.

<h3>What is the Angle Bisector Theorem?</h3>

The Angel Bisector Theorem states that if a ray bisects an angle of a triangle, it dissects the side of the triangle that is opposite to the dissected angle into parts that are proportionate to the adjacent sides.

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See the link below for more about Angle Bisector Theorem of the Triangle:

brainly.com/question/21475560

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