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Delvig [45]
1 year ago
9

Find the length of BC​

Mathematics
1 answer:
Likurg_2 [28]1 year ago
8 0

Answer:

BC = 88.88

Step-by-step explanation:

Comment.

This looks like an example of the cos law.

Givens

AB = 100 m

<A = 60 degrees

AC = 70 m

Cos(60) = 1/2

BC = ?

Formula

BC^2  = AB^2 + AC^2 - 2*AB*AC * Cos(60)

Solution

BC^2 = 100^2 + 70^2 - 2*100*70 * 1/2     1/2 and 2 cancel out

BC^2 = 10000 + 4900 - 7000      

BC^2 = 7900                                             Take the sqr root of both sides

√BC^2 = √7900

BC = 88.88

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Step-by-step explanation:

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Part b. It is given that p = $2000, r = 2.5%, and A = $4000. In this part, t is unknown. Therefore: 4000 = 2000*e^(2.5t). This implies 2 = e^(0.025t). Taking natural logarithm on both sides yields ln(2) = ln(e^(0.025t)). A logarithmic property is that the power of the logarithmic expression can be shifted on the left side of the whole expression, thus multiplying it with the expression. Therefore, ln(2) = 0.025t*ln(e). Since ln(e) = 1, and making t the subject gives t = ln(2)/0.025. This means that t = 27.73 years (rounded to the nearest 2 decimal places)!!!

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