4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer:
a=3
Step-by-step explanation:
5=4a-7
add 7 on both sides
5+7=4a(-7+7)
12=4a
Now divide 4 on both sides
a= 3
PLEASE GIVE BRAINLISET
Answer:
The ordered pairs for 1 and 3 are:
(1,2) (3,8)
Now use the slope formula:
(y2-y1)/(x2-x1)
(8-2)/(3-1)= 6/2 = 3
Step-by-step explanation:
Pretty sure it’s C That one makes the most sense to me please let me know if you get it right
