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Gennadij [26K]
3 years ago
9

Is this triangle acute, right, or obtuse?

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0

Answer:

acute

hope this helps

have a good day :)

Step-by-step explanation:

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Most of the savings accounts at stonebrook community bank are earning simple interest. the formula to calculate the amount of si
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P=i/rt
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4 0
3 years ago
Solve 2x2 + 12x - 14 = 0 by completing the square
vovangra [49]

Answer:

<h2>x = -7 or x = 1</h2>

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\2x^2+12x-14=0\qquad\text{divide both sides by 2}\\\\x^2+6x-7=0\qquad\text{add 7 to both sides}\\\\x^2+2(x)(3)=7\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=7+9\\\\(x+3)^2=16\Rightarrow x+3=\pm\sqrt{16}\\\\x+3=-4\ or\ x+3=4\qquad\text{subtract 3 from both sides}\\\\x=-7\ or\ x=1

5 0
3 years ago
Jaylon makes twice as much an hour as Sam. Sam makes x dollars an hour. Write an expression describing how much Jaylon makes an
Kamila [148]

Answer:

2x dollars an hour. A.

Step-by-step explanation:


2 * x = 2x

3 0
3 years ago
Read 2 more answers
a scale drawing of new york state 2.5 centimeters represents 10 kilometers how many kilometers are represented by 10 centimeters
chubhunter [2.5K]

Answer:

40 Km

Step-by-step explanation:

Cross-multiply (rule of three)

2.5 cm--------10 Km

10 cm-----------x Km

2.5/10 = 10/x

so

x = 100/2.5 = 40 Km

3 0
3 years ago
A parabola can be drawn given a focus of (0,−6) and a directrix of y=−2. Write the equation of the parabola in any form.
topjm [15]

Answer:

y = x^2 - 4

Step-by-step explanation:

The vertex of a parabola is exactly halfway between the focus and the directrix.  If the focus is at (0, -6) and the directrix is the line y = -2, then we do this to locate the vertex:  Draw a vertical line through (0, -6) also crossing the line y = -2.  The y value halfway between y = -6 and y = -2 is y = -4, and the vertex is thus (0, -4).

Using the vertex method, write out the equation of this parabola, starting with the general form y - k = (x-h)^2, where (h, k) is the vertex.  Here h = 0 and k = -4

We get:  y + 4 = (x - 0)^2, or y + 4 = x^2, or y = x^2 - 4.  As a check, let x = 0; y = -4, which is the y-coordinate of the vertex.

7 0
3 years ago
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