This is a system of equations, and I am assuming that you are being asked to solve it.
This is finding the point where these two lines intersect.
The key to solving these algebraically is finding one part in terms of another part and substituting.
We can solve this system by Gaussian elimination, first by multiplying the second equation in its entirety by 2, so that the x-terms will cancel.
We have

and

.
The last equation is rewritten as

.
Now, we cancel the x-terms.



We have our value for y, so we just plug this back into any of the original equations to get x.

Thus, the solution to the system of equations is the point

.
Answer with Step-by-step explanation:
We are given that a sample space
S={a,b,c,d,e}
P(a)=0.1
P(b)=0.1
P(c)=0.2
P(d)=0.4
P(e)=0.2
a.A={a,b,c}
P(A)=P(a)+P(b)+P(c)
P(A)=0.1+0.1+0.2=0.4
b.B={c,d,e}
P(B)=P(c)+P(d)+P(e)=0.2+0.4+0.2=0.8
c.A'=Sample space-A={a,b,c,d,e}-{a,b,c}={d,e}
P(A')=P(d)+P(e)=0.4+0.2=0.6
d.
={a,b,c,d,e}
=P(a)+P(b)+P(c)+P(d)+P(e)=0.1+0.1+0.2+0.4+0.2=1
e.
={c}

Answer:
no triangle
Step-by-step explanation:
SOLUTION: No; . The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
Answer:
1. Yes, Elena is correct because her suitcase needs to weigh 30 pounds or less to avoid the fee and her suitcase weighs 29.8 pounds.
2. x<30
Step-by-step explanation:
The length of the rectangle is = 72 cm
The width of the rectangle is = 56 cm
Area of the rectangle is = 
=
cm²
As given, the other rectangle has the same area as this one, but its width is 21 cm.
Let the length here be = x


Hence, length is 192 cm.
We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.
So, in the new rectangle,constant of variation=k is given by,
or 
Hence, the constant of variation is 