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3 years ago

What is a plane figure bounded by four straight line

Mathematics

1 answer:

Neko [114]3 years ago

6 0

Answer:

A plane figure with 4 sides is called a quadrilateral.

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The value of x and MN if N is between M and P, MP=60, MN=6x-7, and NP=2x+3

Sergio039 [100]

MN + NP = MP
6x - 7 + 2x + 3 = 60
8x - 4 = 60
8x = 64
x = 8

MN = 6(8) - 7 = 56 - 7 = 49

answer
x = 8
MN = 49

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3 years ago

Estimate The problem <br><br> 2,731÷31

Vedmedyk [2.9K]

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your answer should be 90

Step-by-step explanation:

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3 years ago

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Find the size of deb

Akimi4 [234]

Answer:

$4x + 3 = 6x - 53 \\ 6x - 4x = 3 + 53 \\ 2x = 56 \\ x = \frac{56}{2} = 28$

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3 years ago

Find the product -1.2(0.04)

patriot [66]

Answer:

-0.048

Step-by-step explanation:

-1.2 * 0.04 = -1.2 * 4 / 100 = -4.8 / 100 = -).048

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2 years ago

A conical vessels with base radius 5 cm and height 24cm is full of water this water is emptied into a cylindrical vessel of base

Aliun [14]

Answer:

$2\ cm$

Step-by-step explanation:

$We\ are\ given\ that,\\Radius\ of\ the\ conical\ vessel=5\ cm\\Height\ of\ the\ conical\ vessel=24\ cm\\Hence,\\As\ we\ know\ that,\\Volume\ of\ a\ cone=\frac{1}{3}\pi r^2h\\Hence,\\The\ volume\ of\ the\ conical\ vessel=\frac{1}{3}\pi (5)^224= \frac{1}{3}\pi 25*24=200\pi \\Hence,\\The\ volume\ of\ the\ conical\ vessel=The\ amount\ of\ water\ filled\ in\ it\\Hence,\\The\ amount\ of\ water\ filled\ in\ the\ conical\ vessel=200\pi\\Lets\ consider\ the\ cylindrical\ vessel:\\Volume\ of\ a\ cylinder=\pi r^2h$

$As\ we\ are\ not\ said\ that\ the\ cylindrical\ vessel\ was\ empty,\ let\ its\ initial\\ height\ be\ h_1\\Radius\ of\ the\ Cylindrical\ vessel=10\ cm\\Initial\ height\ of\ the\ cylindrical\ vessel=h_1\\Initial\ volume\ of\ the\ cylindrical\ vessel=\pi *10^2*h_1=100h_1\pi \\Initial\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi \\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=Final\ amount\ of\ water\\ in\ the\ cylindrical\ vessel +Amount\ of\ water\ in\ conical\ vessel$

$Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi +200\pi \\Now,\\Let\ the\ final\ height\ be\ h_2\\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=\pi *10^2*h_2=100h_2\pi \\Hence,\\100h_2\pi =100h_1\pi +200\pi \\Hence,\\100h_2=100h_1+200\\100h_2-100h_1=200\\100(h_2-h_1)=200\\h_2-h_1=2\\Hence,\\As\ the\ rise\ in\ level\ is\ the\ difference\ between\ the\ initial\ and\ final\\ heights:\\The\ rise\ in\ level\ of\ water=2\ cm$

8 0

3 years ago

What is a plane figure bounded by four straight line​

What is a plane figure bounded by four straight line