Check the attached file for the solution.
Answer:
1733.28 m³ or approximately 1733 m³
Step-by-step explanation:
Cone - 1/3πr²h
Cylinder - πr²h
Cone - 1/3(3.14)(6)²(10) ⇒ 376.8
Cylinder - (3.14)(6)²(12) ⇒ 1356.48
1356.48 + 376.8 = 1733.28 m³
Approximately 1733 m³
The expression is equivalent to 49/8.
Well, AEB is 28, and CED is 65,and you want to add them, so that would be 65+28, which equals 80+13=93, so the answer is b.
To solve for the surface area of the pyramid, we make use
of the formula:
A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))
where,
l and w are the base of the pyramid = 100 mm
h is the height of the pyramid = 75 mm
Substituting the given values into the equation:
A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100
/ 2)^2 + 75^2))
A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)
A = 20,148.90 mm^2
Therefore the surface area of the pyramid is about 20,149
mm^2.
