Answer:
4
Step-by-step explanation:
;)
The combinations of ordered triplets that are possible is equal to: A. 18.
<h3>How to find the possible number of ordered triplet?</h3>
Since the common difference (d) between the consecutive terms in an arithmetic progression (AP) is constant, we have:
d = y - x = z - y
Rearranging the terms, we have:
x = y - d
z = y + d
From the given equation:
x + y + z = 30
y - d + y + y + d = 30
3y = 30
y = 30/3
y = 10.
So the arithmetic progression (AP) is given by:
(10 - d), 10, (10 + d)....
Since the common difference (d) is a natural number which would be from 1 to 9, the combinations of ordered triplets that are possible is as follows:
Number of possibilities = 9 × 2
Number of possibilities = 18.
Read more on arithmetic progression here: brainly.com/question/18828482
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<u>Complete Question:</u>
If x, y, z are three natural numbers in A.P. such that x + y + z = 30 then the possible number of ordered triplet (x, y, z) is?
A. 18
B. 19
C. 20
D. 21
Answer:
306.
Step-by-step explanation:
Firstly, we are aware 100% of 680 is obviously 680,
Next, we know half of a 100% is 50% therefore half of 680 is 340.
Then, we know 45% is 5% less than 50%
To find 5% of a number mentally, divide it by 10 as 100÷5=20
680÷20=34
Lastly 50% subtracted by 5%: 340-34=306.
Now we know, 45% of 680 is 306.
<em>Hope this helps.</em>
<em>Hope this helps.Please mark BRAINLIEST.</em>
The original answer is : 19.872
and
The but it rounded to 19.87
Therefore your answer is "19.87 "