Please help me!! I really don't know how to do this!!

Mathematics

1 answer:

Nimfa-mama [501]2 years ago

3 0

R*F = 5LF, R*M = 9LM, L*F + L*M = 18, R*F + R*M = 122.
RF=50, LF=10, RM=72, LM=8. Fill in the graph with this info and assume there aren't people that are transgender

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Can some please help me I will mark u brilliant

brilliants [131]

Question 2: -4/3

Question 3: -7/20

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2 years ago

jake spends 2 hours on each homework assignment and he had 3 assignments each day.orlando spend 2 hiurs on each homework assignm

Andrej [43]

Ok so u have to multiply for this one

Work *Jake*:

So he spends 2 hours on each assignment. He has 3 assignments so u have to do :
2*3=6
He spend 6 hours a day doing home work so now u have to multiply that by 30:
6*30=180

Work *Orlando*:

So he spends 2 hours on each homework. He has 2 sheets each do so u have to multiply 2 and 2:
2*2=4

He spends 4 hours a day doing homwork so u have to multiply it by 30:
4*30=120

Answer:

So Jake spends 130 hours
Orlando spends 120 hours

Add both together:
120+130=250

They spend 250 hours together on work in 30 days/

4 0

2 years ago

Read 2 more answers

Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov

mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

$2t=(m+\frac{1}{2} ).\frac{\lambda}{n}$

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

$t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm$