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2 years ago

10

What is the difference between the formula of the volume of the cylinder and the volume of a cone? What do the formulas have in

common?

1 answer:

Margaret [11]2 years ago

6 0

Answer:

The volume of the cylinder is 3 times the volume of the cone

Step-by-step explanation:

The formula for the volume of the cylinder is given by :

$V_{cy}=\pi r^2 h$ .....(1)

Where

r and h are the radius and the height of the cylinder

The formula for the volume of the cone is given by :

$V_{cone}=\dfrac{1}{3}\pi r^2h$ ...(2)

From equation (1) and (2),

$\dfrac{V_{cy}}{V_{cone}}=\dfrac{\pi r^2 h}{\dfrac{1}{3}\pi r^2 h}\\\\=3\\\\V_{cy}=3\times V_{cone}$

So, the volume of the cylinder is 3 times the volume of the cone.

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$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

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where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
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The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

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