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frez [133]
3 years ago
14

The Art Club collected $15 from each of its 17 members for dues. It then had $300 in its account. Assume the relationship is lin

ear. Find and interpret the rate of change and the initial value.
Mathematics
1 answer:
belka [17]3 years ago
6 0

The "rate of change" is presumed to refer to the rate at which the balance in the bank account changes as dues are collected from Art Club members. It increases by $15 for each new collection, so we can say ...

... the rate of change is $15 per member.

We further presume that the problem intends the "initial value" to refer to the fact that the 17 × $15 = $255 does not match the full amount of the current Art Club account balance ($300). So, there must have been some balance in the account before collection started. We can interpret that $45 "initial value" as ...

... the account balance before dues collection started is the initial value.

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Answer:

17

Step-by-step explanation:

Properties used:-

All sides of rhombus are equal therefore in the triangles

EQUAL SIDE OPPOSITE TO ANGLES, ANGLES BECOME EQUAL

then we use alternate interior angles

Then we get,

3x-11=x+23

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2 years ago
Solve the multi step literal equation: solve equation for A b^2A^2-3g=q
I am Lyosha [343]

Answer:

A = ± \sqrt{\frac{q+3g}{b^2} }

Step-by-step explanation:

Given

b²A² - 3g = q ( add 3g to both sides )

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3 years ago
Volume is always measured in square units. True False
bogdanovich [222]
Hello,

The answer is option B "false".

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If you need anymore help feel free to ask me!

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4 0
3 years ago
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The following equation is being multiplied by the LCD. Complete the multiplication to eliminate the denominators
frosja888 [35]

Answer:

(x+2)(x-2) -1(3x)=(x-3)(x-2)

Step-by-step explanation:

x+2/3x - 1/x-2 = x-3/3x

\frac{x+2}{3x}-\frac{1}{x-2}=\frac{x-3}{3x}

LCD is (3x)(x-2). so we multiply the whole equation by LCD

(3x)(x-2)(\frac{x+2}{3x}-\frac{1}{x-2}=\frac{x-3}{3x})

We multiply each term by LCD

(3x)(x-2)(\frac{x+2}{3x})-(3x)(x-2)(\frac{1}{x-2})=(3x)(x-2)(\frac{x-3}{3x})

(x+2)(x-2) -1(3x)=(x-3)(x-2)

4 0
3 years ago
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A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

5\cdot 36^5

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

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ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8

oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

7 0
3 years ago
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