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11111nata11111 [884]
4 years ago
13

Using the equation 2H2+O2 = 2H2I, if 192 g if oxygen reacts completely, how many grams of hydrogen must react with it

Chemistry
1 answer:
dimaraw [331]4 years ago
7 0
I assume there is a typo in the equation.  It is H2O instead of H2I.

The ratio of H2 and O2 that react with each other is 2:1.  To find out the grams of H2, we need to first find out the moles of O2 and H2.

Moles of O2 = mass of O2/molar mass of O2 = 192g/32g/mol = 6 mol.  Therefore, the moles of H2 = 6mol *2 = 12 mol.

So the mass of H2 that reacts with O2 = moles of H2 * molar mass of H2 = 12 mol * 2 g/mol = 24 g

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An iron storage tank is placed in the ocean with no cathodic protection. a. What is the electrolyte in this reaction? b. As the
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Answer:

Iron is being oxidized at the anode and water is acting as the electrolyte.

Explanation:

When iron is exposed to oxygen and water , the rusting of iron takes place.

<u>The reaction taking place at anode : Oxidation of iron.</u>

{anode:}\;\text{Fe}(s)\;{\longrightarrow}\;\text{Fe}^{2+}(aq)\;+\;2\text{e}^{-}

The reaction taking place at cathode : Reduction of oxygen in the air.

{cathode:}\;\text{O}_2(g)\;+\;4\text{H}^{+}(aq)\;+\;4\text{e}^{-}\;{\longrightarrow}\;2\text{H}_2\text{O}(l)  

The overall reaction:

{overall:}\;2\text{Fe}(s)\;+\;\text{O}_2(g)\;+\;4\text{H}^{+}(aq)\;{\longrightarrow}\;2\text{Fe}^{2+}(aq)\;+\;2\text{H}_2\text{O}(l)

The rust that is hydrated iron(III) oxide can form iron(II) ions which can react further with oxygen.

4\text{Fe}^{2+}(aq)\;+\;\text{O}_2(g)\;+\;(4\;+\;2x)\;\text{H}_2\text{O}(l)\;{\longrightarrow}\;2\text{Fe}_2\text{O}_3{\cdot}x\text{H}_2\text{O}(s)\;+\;8\text{H}^{+}(aq)

Thus, from the above reactions ,

Iron is being oxidized at the anode and water is acting as the electrolyte.

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4 years ago
An aqueous solution contains 300 parts per million of KOH. Determine the number of grams of KOH present in 1000 grams of this so
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300 ppm = 300 g KOH / 1000000 g solution

mass KOH = 300 g KOH / 1000000 g solution (1000 g solution)
mass KOH = 0.3 g KOH
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