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nydimaria [60]
3 years ago
11

When mixtures of gaseous h2 and gaseous cl2 react, a product forms that has the same properties regardless of the relative amoun

ts of h2 and cl2 used. how is this result interpreted in terms of the law of definite proportions? when a volume of h2 reacts with an equal volume of cl2 at the same temperature and pressure, what volume of product having the formula hcl is formed?
Chemistry
1 answer:
lilavasa [31]3 years ago
4 0
According to Dalton's Atomic Theory, the <em>Law of Definite Proportion is applied when a compound is always made up by a fixed fraction of its individual elements.</em> This is manifested by the balancing of the reaction.

The reaction for this problem is:

H₂ + Cl₂ → 2 HCl

1 mol of H₂ is needed for every 1 mole of Cl₂. Assuming these are ideal gases, the moles is equal to the volume. So, if equal volumes of the reactants are available, they will produce twice the given volumes of HCl.
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Which neutral atom has 151 neutrons and 96 electrons
Lelechka [254]
<span> Curium (Cm)  is the answer.

Hope this helps.</span>
3 0
3 years ago
Read 2 more answers
Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer
lidiya [134]

The question is incomplete, the complete question is

Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer? Ag^+ + 1 e^- rightarrow Ag Edegree = 0.7993 V V^2+ + 2e^- right arrow V E degree =-1.125 V Ag+ is reduced V is oxidized 1.924 V V2^+ is reduced Ag is oxidized I and II III, IV, and V I, II, and III III only IV and V

Answer:

only IV and V

Explanation:

If we look at the values of reduction potential for the two species, we will discover that vanadium has a negative reduction potential indicating its tendency towards oxidation.

On the other hand, solve has a positive reduction potential indicating a tendency towards reduction.

This implies that vanadium must be oxidized and silver reduced and not the not her way ground? Hence the answer above.

7 0
2 years ago
If 3.6 g of aluminum completely reacts, how much Al2O3 (in grams) can be produced
marissa [1.9K]

The amount in grams of  Al₂O₃ produced is approximately 6.80 g.

Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:

AL + O₂ → Al₂O₃

Let's balance it

4AL + 3O₂ → 2Al₂O₃

4 moles of Aluminium reacts with 3 moles of Oxygen molecules to produce 2 moles of Aluminium oxide. Therefore,

Since, aluminium reacts completely, it is the limiting reagent in the reaction. Therefore,

Atomic mass of AL = 27 g

Molar mass of  Al₂O₃ = 101.96 g/mol

4(27 g) of AL gives 2(101.96 g) of  Al₂O₃

3.6 g of AL will give ?

cross multiply

mass of  Al₂O₃ produced = 3.6 × 203.92 / 108   = 734.112 / 108 = 6.797

mass of  Al₂O₃ produced = 6.80 g.

read more: brainly.com/question/23982245?referrer=searchResults

8 0
3 years ago
Consider the following reaction.
Ivan

Answer:

162 g Fe₂O₃

Explanation:

To find the mass of Fe₂O₃, you need to (1) convert grams C to moles C (via molar mass from periodic table), then (2) convert moles C to moles Fe₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe₂O₃ to grams (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (C): 12.011 g/mol

2 Fe₂O₃(s) + 3 C(s) ---> 4 Fe(s) + 3 CO₂(g)

Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (Fe₂O₃): 159.684 g/mol

18.3 g C           1 mole            2 moles Fe₂O₃          159.684 g
--------------  x  ----------------  x  -------------------------  x  -----------------  = 162 g Fe₂O₃
                        12.011 g              3 moles C                 1 mole

5 0
1 year ago
What is the key element fountain all carbohydrates lipids proteins and nucleus acid
just olya [345]
Carbon is found in all four.
6 0
3 years ago
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