Answer:
See Explanation
Explanation:
Metallic bonds involve attraction between electrons and positively charged metal ions. The metals are ionized and electrons form a sea of valence electrons. These loosely bound electrons surround the nuclei of the metals.
The presence of this sea of electrons explains the fact that metals conduct electricity and heat due to the free valence electrons.
Due to the nature of the bonding between metal atoms,metals are malleable and ductile.
Due to the strong electrostatic interaction between metal ions and electrons, the metallic bond is very strong and is very difficult to break thereby accounting for the greater strength of metals as the size of the metallic ion decreases.
Answer:
47, 68, 47
Explanation:
Let's consider the following isotope: ¹¹⁵Ag.
If we look in the Periodic Table, the atomic number of Ag is 47, that is, silver has 47 protons.
Since ¹¹⁵Ag is neutral it must have the same number of protons that of electrons. Then, it also has 47 electrons.
The number 115 in ¹¹⁵Ag stands for the mass number, which is the sum of protons and neutrons. Then, the number of neutrons is:
p⁺ + n⁰ = 115
n⁰ = 115 - p⁺ = 115 - 47 = 68
The number of protons, neutrons, and electrons in ¹¹⁵Ag is: 47, 68, 47.
Answer:
pH = 11.7
Explanation:
<u>Given:</u>
[OH-] = 0.00500 M
<u>To determine:</u>
pH of the solution
<u>Explanation:</u>
pH refers to the H+ ion concentration in a given solution whereas pOH indicates the OH- ion concentration.
pH and pOH are related by the following equation:
Here:
![pH = -log[H+]\\\\pOH = -log[OH-]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%2B%5D%5C%5C%5C%5CpOH%20%3D%20-log%5BOH-%5D)
When OH- = 0.00500 M
Based on equation(1):
Answer;
= C3H5
Explanation and solution;
1 mole of CO2 contains 44 g, of which 12 g are carbon
Thus, mass of carbon in 9.32 g will be;
(12/44) × 9.32 g = 2.542 g
Mass of Hydrogen in 3.18 g of water;
= (2/18) × 3.18 g = 0.353 g
we then find the number of moles;
Moles of carbon ; 2.542 /12 = 0.2118 moles
Moles of Hydrogen = 0.353 moles
The ratios of C ; H ;
= 1 : 0.353 /0.2118
= 1 : 5/3
= 3: 5
Therefore; the empirical formula of the hydrogen carbon is; C3H5
