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3 years ago

Every time I go to type a question it does this over and over where I can’t even type the question I’m looking for. Someone help

Mathematics

1 answer:

den301095 [7]3 years ago

7 0

Answer: try checking your Wifi source and reopen the site if it's an app delete it then reinstall it another thing you can try is to restart your device or ask an IT in your family or one you know for help hope this works! :D

Step-by-step explanation:

You might be interested in

1. What is a polygon? 2. What makes a polygon a regular polygon?

sergey [27]

Answer:

Step-by-step explanation:

A polygon is a simple, closed curve in the plane composed of finite number of line segments.

That it connects back where it started, and that its perimiter can be mesured.

6 0

3 years ago

Help? I can't seem to understand arithmegic sequence.

katrin2010 [14]

A sequence $\{a_n\}$ is arithmetic if the difference between consecutive terms is some fixed number, regardless of which pair of consecutive terms you pick out of the sequence.

For example, the following sequences are arithmetic:

1, 2, 3, 4, 5, 6, ... (difference = 1)

-25, -20, -15, -10, -5, ... (difference = 5)

2. Carla's sequence is not arithmetic, because the differences between consecutive terms are all different:

13 - 11 = 2

17 - 13 = 4

25 - 17 = 8

She can adjust the sequence by changing the last two numbers to 15 and 17, since this makes the difference fixed:

13 - 11 = 2

15 - 13 = 2

17 - 15 = 2

and so on.

3. The sequence

45, 48, 51, 54, ...

is arithmetic with difference 3 between terms. Recursively, we can write the $n$ th term, $a_n$ , in terms of the previous, $(n-1)$ th term, $a_{n-1}$ :

$a_n=a_{n-1}+3$

By this definition, we can just as easily write the $(n-1)$ th term in terms of the $(n-2)$ th term:

$a_{n-1}=a_{n-2}+3$

Then, substituting this into the previous equation, we have

$a_n=(a_{n-2}+3)+3=a_{n-2}+2\cdot3$

We can continue this process to write $a_n$ in terms of $a_1$ :

$a_{n-2}=a_{n-3}+3\implies a_n=a_{n-3}+3\cdot3$

$a_{n-3}=a_{n-4}+3\implies a_n=a_{n-4}+4\cdot3$

and so on. (You might notice that the subscript of the term on the right side, and the number of 3s being added, together sum to $n$ .) The pattern continues down to

$a_n=a_1+(n-1)\cdot3$