All categories

3 years ago

Please Help, GodBless

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

7 0

Answer:

-3/2

Step-by-step explanation:

The rate of change is the same as slope

You might be interested in

BRAINLIEST BRAINLIEST <br> please answer thank you

Anna [14]

Answer:

y + x = 7

Step-by-step explanation:

Standard form should be

y - 9 = -(x+2)

y = -x -2 +9

y + x = 7

6 0

3 years ago

Read 2 more answers

An item is regularly priced at $90 . leila bought it at a discount of 60% off the regular price. how much did leila pay?

forsale [732]

90(.4) = 36

Leila payed $36

3 0

3 years ago

Libby needs to cut pieces of oak molding that are 3/4 yard long. She has 2 yards of oak molding. How many pieces can she cut? Ho

jek_recluse [69]

Answer: She can make two 3/4 yards long of oak molding. She will have half of the second one left over.

Step-by-step explanation:

3 0

3 years ago

In a particular game, a fair die is tossed. If the number of spots showing is either four or five, you win $1. If the number of

TiliK225 [7]

Answer:

The probability that you win at least $1 both times is 0.25 = 25%.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either you win at least $1, or you do not. Games are independent. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of winning at least $1 on a single game:

The die has 6 sides.

If it lands on 4, 5 or 6(either of the three sides), you win at least $1. So

$p = \frac{1}{2} = 0.5$

You are going to play the game twice.

This means that $n = 2$

The probability that you win at least $1 both times is

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.5)^{2}.(0.5)^{2} = 0.25$

The probability that you win at least $1 both times is 0.25 = 25%.

4 0

2 years ago

Given the figure below, find the values of x and z

Ratling [72]

$(13x-85)^o=97^o\\\\13x-85=97\ \ \ |+85\\\\13x=182\ \ \ |:13\\\\x=14$

$z^o+97^o=180^o\ \ \ |-97^o\\\\z^o=83^o$

Answer: x = 14; z = 83

4 0

3 years ago