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VikaD [51]
3 years ago
5

1. Draw a histogram from all the data. Starting at the bottom row, for each set of 10 flips, place an “x” in the column correspo

nding to the number of heads that set produced. Your histogram should look similar to the example below: 2. Calculate the mean and standard deviation. mean = _____, standard deviation = _____ 3. Calculate the percent of the data that is within 1, 2, and 3 standard deviations of the mean. within 1 standard deviation = _____% within 2 standard deviations = _____% within 3 standard deviations = _____% 4. Compare your results to a normal distribution. Interpret any differences.
Mathematics
1 answer:
iris [78.8K]3 years ago
4 0

Answer:

K

Step-by-step explanation:

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Will give brainlist if you can help!
kkurt [141]

Answer: 12:5

Step-by-step explanation:

4 0
3 years ago
What do you think the answer is, please hurry
vazorg [7]
There is an 18% chance that out of the 3 students she asks, 3 would be in a band. I hope this helped ^^
6 0
3 years ago
ANSWER QUICK PLEASE THANK YOU!!! 7 1/2 divided by (4 1/2 - 5 1/8)=
DiKsa [7]

Answer:

7 1/2 divided by (4 1/2 - 5 1/8)=-12

Step-by-step explanation:

PLZZ MARK BRAINLIEST!!!!

Answer is -12

8 0
2 years ago
Please Help ASAP!!
Brilliant_brown [7]

Answer:

The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.

Step-by-step explanation:

In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't.  Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype.  However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.  

4 0
3 years ago
Identify the mean, median, and mode for the dot plot below.01 2 3 4MathBits.comNumbers of Brothers and SistersMeanMedianMode =
telo118 [61]

The mean, median and mode is 2 of the given data from the dot plot.

Given, the table is :

Number of brothers and sisters  0,0,1,1,1,2,2,2,2,2,3,3,3,4,4

First the mean

Mean = average which = sum of data points / # of data points

Sum of data points = 0+0+1+1+1+2+2+2+2+2+3+3+3+4+4 = 30

# of data points ( count the number of dots ) = 15

So average (mean) = 30/15

= 2

Next lets find the median.  

The median is the middle value.

We can find the median by listing the values and then meeting at the middle of the values

So we have 0,0,1,1,1,2,2,2,2,2,3,3,3,4,4

the list is odd, so we use median = n+1/2

= 15+1/2

= 16/2

= 8th term

= 2

Mode is simply the value that appears most.

The value that appears the most is 2 as it appears five times which is the most out of any other value.

Hence we get the mean, median and mode.

Learn more about Statistics here:

brainly.com/question/26941429

#SPJ9

               

6 0
1 year ago
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