Question

Which of the following theorems verifies that ABC~WXY?

Answer 1

Answer:

The correct answer is option B. AA

Step-by-step explanation:

Given two triangle:

$\triangle ABC$  and $\triangle WXY$.

The dimensions given in $\triangle ABC$ are:

$\angle A = 27^\circ\\\angle B = 90^\circ$

We know that the sum of three angles in a triangle is equal to $180^\circ$.

$\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 27+90+\angle C=180^\circ\\\Rightarrow \angle C = 63^\circ$

The dimensions given in $\triangle WXY$ are:

$\angle Y = 63^\circ\\\angle X = 90^\circ$

We know that the sum of three angles in a triangle is equal to $180^\circ$.

$\angle W+\angle X+\angle Y = 180^\circ\\\Rightarrow \angle W+90+63=180^\circ\\\Rightarrow \angle W = 27^\circ$

Now, if we compare the angles of the two triangles:

$\angle A = \angle W = 27^\circ\\\angle B = \angle X= 90^\circ\\\angle C = \angle Y= 63^\circ$

So, by AA postulate (i.e. Angle - Angle) postulate, the two triangles are similar.

$\triangle ABC \sim \triangle WXY$ by AA theorem.

So, correct answer is option B. AA