Paul's car is 18 feet Long he is making a model of his car that is 1/8 the actual size what is the length of the model

Jenny is 12 years older than Nancy. Five years ago Jenny was three times as old as Nancy. How old is each now?

mote1985 [20]

Answer:

Jenny = 23 | Nancy = 11

Step-by-step explanation:

8 0

3 years ago

Find a sum equivalent to the product 6(y+x)

Naily [24]

Distribute the six: 6y+6x

3 0

2 years ago

Evaluate the following

IRINA_888 [86]

(a) $[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

Answer:

$[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5*2.5 }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5}{1} ]^{2}$

*canceling 2.5 in numerator and denominator*

$= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925$

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) $[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3} ] ^{2}$

Answer:

$[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\$

*using $[x^{a}]^b = x^{ab}$ *

$= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}$

*Again, using $[x^{a}]^b = x^{ab}$ *

$= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} } \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1$

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

3 0

2 years ago

Again can someone help pls sorry :

IgorLugansk [536]

Answer:

13.5

Step-by-step explanation:

the two medians are 12 and 15. you need to then find the average. 12+15=27. 27/2=13.5.

7 0

3 years ago

Out of the 150 students at a summer camp, 72 signed up for canoeing. there were 23 students who signed up for trekking, and 13 o

True [87]

Answer:

Approximately 45% students signed up for neither canoeing or trekking.

Step-by-step explanation:

First we subtract the number of the students who signed up from the number of the total students to find the number of the students who did not signed up for either.

But there are 13 students who signed up canoeing and also for trekking.

Hence the number of students they signed up for activity is

72 + 23 - 13 = 82

And the number of students they not signed up for any activity is

150 - 82 = 68

so 68 students signed up neither for trekking nor canoeing. The percentage of those students are :

$\frac{68}{150}$ × 100 = 45.3333%

Approximately 45% students signed up for neither canoeing or trekking.

8 0

2 years ago