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3 years ago

What will be the perimeter and the area of the rectangle below if it is enlarged using a scale factor of 6.5?

Mathematics

2 answers:

vaieri [72.5K]3 years ago

3 0

The perimeter of the given rectangle is
2(6 cm + 8 cm) = 28 cm
The area of the given rectangle is
(6 cm)*(8 cm) = 48 cm^2

The larger rectangle will have a perimeter of
6.5*28 cm = 182 cm
The larger rectangle will have an area of
6.5^2*48 cm^2 = 2028 cm^2 . . . . . note the scale factor is squared for area

The appropriate choice is the 3rd one, ...
<span>Perimeter = 182 cm, area = 2,028 cm^2</span>

zysi [14]3 years ago

3 0

Answer:

Perimeter = 182 cm, area = 2,028 cm^2

Step-by-step explanation:

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A = {1, 3, 5, 7, 9} B = {2, 4, 6, 8, 10} C = {1, 5, 6, 7, 9} A ∩ (B ∪ C) =

vovikov84 [41]

A = {1, 3, 5, 7, 9}
B = {2, 4, 6, 8, 10}
C = {1, 5, 6, 7, 9}

(B ∪ C) = {1, 2, 4, 5, 6, 7, 8, 9, 10}
so
A ∩ (B ∪ C) = {1, 5, 7 , 9}

6 0

3 years ago

Three kids play tennis at the same tennis courts. Mark plays every fourth day, David plays every seventh day and Bryan plays eve

jonny [76]

Answer:

Wednesday (9 weeks later) = 10th October.

Step-by-step explanation:

We label the days with the initials of the names.

M= 4

D = 7

B = 6

LCM of 6 +7 = 42

LCM of 6+7 + 4 = 84

We find 84 is the amount of days we need to add on to july 18th

We first find the weeks 84/7 = 9 weeks.

As Wednesday July 18th is exclusive it would be 84 days after this event.

18+ 84 = 102 days.

31 days in july = 31

31 days in Aug = 31

30 days in Sept = 30

= 92

102-92 = 10

We now know date is Wednesday 10th October

We can check 84 days = 9 weeks

13 days in July makes 31st july

31 days in Aug makes 31st Aug

30 days in Sept makes 30th Sept

= 74 days + 10 days = 84

10th October is the checked date and we know it is also a Wednesday as Wednesday had stayed exclusive and prove that there are 7 days in the week to account x 9, to account for an exact 9 weeks later duration.

6 0

3 years ago

Read 2 more answers

An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden

Butoxors [25]

Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0$

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

$p_1=X_1/n_1=180/500=0.36$

The sample 2, of size n2=600 has a proportion of p2=0.25.

$p_1=X_1/n_1=150/600=0.25$ .

The difference between proportions is (p1-p2)=0.11.

$p_d=p_1-p_2=0.36-0.25=0.11$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{180+150}{500+600}=\dfrac{330}{1100}=0.3$

The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=2\cdot P(t>3.964)=0.000078$

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.0277=0.0544$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.11-0.0544=0.05561\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.11+0.0544=0.16439$

The 95% confidence interval for the population mean is (0.0556, 0.1644).

5 0

3 years ago

Can someone help me understand why the mean travel for women is greater than the mean travel for men?

VashaNatasha [74]

I don't understand your question? the table is comparing between average people ( men dark gray/ women light grey) and the time they take to get to their work...

7 0

3 years ago

To use ASA to prove that SEA= PEN, one must show that _____ by the vertical angle theorem.

ruslelena [56]

Answer:

the answer for ur question is:

the answer for ur question is:B

5 0

2 years ago