Answer:
Cost of each daylilies = $3
Cost of each ivy pot = $3
Step-by-step explanation:
Given:
Cost of 4 daylilies and 4 ivy = $24
Cost of 4 daylilies and 8 ivy = $36
Find:
Cost of each daylilies
Cost of each ivy pot
Computation:
Assume;
Cost of each daylilies = a
Cost of each ivy pot = b
So,
4a + 4b = 24....... eq 1
4a + 8b = 36 ....... eq 2
Eq2 - Eq1
8b - 4b = 36 - 24
4b = 12
b = 3
So,
Cost of each ivy pot = $3
4a + 4b = 24
4a + 4(3) = 24
4a + 12
a = 3
Cost of each daylilies = $3
Answer:
20= v+9+( -16 )
20= v-( 7 )
27= v
Step-by-step explanation:
Adding a negative is the sane as subtracting. Add like terms. Add 7 to both sides. 27= v
Answer:
-I haven't done this, but I have copied and pasted from another question and answer from the user syed514:
Graphing is one way to do the problem.But sometimes, graphing it is hard to do.So here’s an algebraic method.
If M(m1, m2) is the midpoint of two points A(x1, y1) and B(x2, y2),then m1 = (x1 + x2)/2 and m2 = (y1 + y2)/2.In other words, the x-coordinate of the midpointis the average of the x-coordinates of the two points,and the y-coordinate of the midpointis the average of the y-coordinates of the two points.
Let B have coordinates (x2, y2) in our problem.Then we have that 6 = (2 + x2)/2 and 8 = (3 + y2)/2.
Solving for the coordinates gives x2 = 10, y2 = 13
58 if you add the two numbers then subtract the answer from 180 that’s the answer
Answer:
80
Step-by-step explanation:
The trick is to pick something that should be very easy to get an answer to. If you use a calculator, you are not estimating. 80 divide by 4 is like 8 divide by 4 which gives you 2. Then just add a zero. Here's another one you can try. Put your calculator away to do it. 12 chicken noodle soup cans cost 14 dollars. About how much does 1 can cost
no cheating. No calculator. Is the cost of 1 can more or less than a dollar? If you said more, you've estimated correctly.
Try it the other way. Suppose one can of the soup costs 0.95 cents. How many will 12 cans cost? More or less than 12 dollars.
If you said less, you are estimating correctly. The most useful gift you can take away from any math class is estimation.
