The zeroes of the polynomial functions are as follows:
- For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
- For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
- For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
<h3>What are the zeroes of a polynomial?</h3>
The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.
The polynomials are given as follows:
f(x) = 2x(x - 3)(2 - x)
f(x) = 2(x - 3)²(x + 3)(x + 1)
f(x) = x³(x + 2)(x - 1)
For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.
Learn more about polynomials at: brainly.com/question/2833285
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He can either measure the third side length, apply the Pythagorean theorem to find the height of the triangle, and then calculate the area, or he can find the measure of the included angle between the known side lengths and use trigonometry to express the height of the triangle and then determine the
area of the triangle
Answer:
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Step-by-step explanation:
Answer:
its 0.35
Step-by-step explanation:
Answer:
a) x1 = 6 and x2 = -2
b) -2
Step-by-step explanation:
a)
To find the roots of the quadratic equation, we can use the Bhaskara's formula:
Delta = b^2 - 4ac
Delta = (-4)^2 - 4*1*(-12) = 64
sqrt(Delta) = 8
x1 = (-b + sqrt(Delta)) / 2a
x1 = (4 + 8) / 2
x1 = 6
x2 = (-b - sqrt(Delta)) / 2a
x2 = (4 - 8) / 2
x2 = -2
b)
The roots are 6 and -2, so the smaller root is -2
