Sorry, I'm not sure.
I would suggest asking a trusted adult or teacher or redoing the lesson. Cheating isn't a good path: you will not do well in the future if you always search for answers on the internet.
Answer:
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
Step-by-step explanation:
We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.
We have to calculate a 95% confidence interval for the proportion.
The sample proportion is p=0.26.
The standard error of the proportion is:
The critical z-value for a 95% confidence interval is z=1.96.
The margin of error (MOE) can be calculated as:

Then, the lower and upper bounds of the confidence interval are:

The 95% confidence interval for the population proportion is (0.192, 0.328).
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
25,000 - 8,500 = 16,500
16,500 :1250 = 13 years and 2 months
$1,800 (10%) = $180
jay pays 10% of the expenses beyond the deductible so you multiply the amount beyond the deductible by 10%.
$1,800 - $180 = $1,620
or
$1,800 (90%) = $1,620
you subtract what jay pays from the total or you multiply the total by 90%
jay pays $180 of the expenses past the deductible (not including his $200 deductible) and his insurance company pays $1,620.