Answer:
ligand; ions; ligand; ions; nervous system
Explanation:
Ligand-gated ion channels are transmembrane protein complexes that open when they bind to their corresponding ligands (e.g., neurotransmitters). This type of receptor is known to modulate the synaptic transmission between neuron cells or neuron and muscle cells. In the nervous system, ligand-gated ion channels located at sites of synaptic contact determine the ion flow in response to neurotransmitter binding. Some examples of ligand-gated ion channels include gamma-aminobutyric acid A (GABA-A) and nicotinic cholinergic receptors.
The answer is restriction enzymes. These staggered ends are important in recombination of DNA since they allow DNA strands with complementary sticky ends to be easily joined into one piece by DNA ligase. Other restriction enzymes produce blunt ends. These are harder to join by DNA ligase. An example of a restriction ezyme if EcoRI
<span>Stem
cells develop into different types of cells as an organism grows. They also act
as internal repair systems. They divide without limit so as to replenish other
types of cells as long as the concerned organism is still alive. Stem cells
that develop to form either B cells or NK cells are normally found in the bone
marrow.</span>
Answer:
The correct option is;
D. 45%
Explanation:
From the Hardy- Weinberg law, we have;
p² + 2·p·q + q² = 1
p + q = 1
Where:
p = Dom inant allele frequency in the population
q = Recessive allele frequency in the population
p² = The percentage of individuals in the population that are hom ozygous dominant
q² = The percentage of individuals in the population that are homo zygous recessive
2×p×q = The percentage of hete rozyous individuals in the population
The number of individuals that express the recessive phenotype = 86
The number of individuals in the population = 200
The percentage of individuals that express the recessive phenotype, q² = 86/200 = 0.43
Therefore;
q = √0.43 = 0.656
p + q = 1
p = 1 - q = 1 - 0.656= 0.344
∴ The frequency of individuals that express the do minant phe notype, p = 0.344
The percentage of heterozyous individuals in the population = 2×p×q × 100 = 2 × 0.656 × 0.344 × 100 = 45.15% ≈ 45%
Answer:
D
Explanation:
Addition of hydroxide ions will decrease its acidity and make it more basic.
