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wlad13 [49]
4 years ago
10

Suppose that you are running down the street at 6 m/sec. You see your dog ahead and speed up to 10 m/sec over 20 sec to catch hi

m. What is your acceleration in m/s2?
Physics
2 answers:
Sergeu [11.5K]4 years ago
5 0
Acceleration=( change in velocity)/ (time taken),
= (10-6)/20 = 0.2m/s^2
dezoksy [38]4 years ago
3 0

Answer:

The answer is 0.2 m/s^{2}.

Explanation:

We can calculate the acceleration since we know that acceleration is change in velocity over time or:

a =Δv/t

where a = acceleration, Δv = change in velocity, t = time.

We know that Δv = v2 - v1          where, v2 = 10 m/s and v1 = 6 m/s

Therefore,

a = \frac{10 - 6}{20}=\frac{4}{20}= 0.2 m/s^{2}

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What is the emf of this cell under standard conditions? Express your answer using three significant figures.
madreJ [45]

Complete Question

A voltaic cell utilizes the following reaction and operates at 298 K:

3Ce4+(aq)+Cr(s)→3Ce3+(aq)+Cr3+(aq).

What is the emf of this cell under standard conditions? Express your answer using three significant figures.

Answer:

The value is E^o_{cell}  = 2.35 V

Explanation:

From the question we are told that

   The ionic equation is  

               3 Ce^{4 +}  _{(aq)}  +  Cr _{(s)}  \to  3 Ce^{3+} _{(aq)}  +  Cr^{3r}  _{(aq)}

Now under standard conditions the reduction  half reaction  is

      Ce^{4+}  + e \to Ce^{3+}  ; \ \ E^o_r  =  1.61 V

And the oxidation half reaction is

      Cr^{3+}  +  3e^{-}  \to  Cr ; \    \  \  E^o_o  =  - 0.74 V

The emf of this cell under standard conditions  is mathematically represented as

     E^o_{cell}  =  E^o _r -  E^o _o

substituting values

     E^o_{cell}  =  1.61  - (- 0.74)

    E^o_{cell}  = 2.35 V

     

3 0
3 years ago
Scientists observed a rocky, rotating object orbiting in space. It was 250 km wide. The rocky object was located several times f
mote1985 [20]

The rocky object orbiting in space is most likely referred to as an asteroid.

<h3>What is an Asteroid?</h3>

This is referred to a rocky object which revolve around the sun and are considered too small to be called a planet.

Asteroids was observed with the use of a telescope and is around 250 km wide thereby making it the most appropriate choice.

Read more about Asteroids here brainly.com/question/11996385

4 0
3 years ago
A racecar traveling at a velocity of 18.5 m/s, accelerates at a rate of 2.47 m/s2 and covers a distance of 79.78 m. Determine th
Vesna [10]

Answer:

The final velocity of the race car is 27.14 m/s

Explanation:

Given;

initial velocity of the race car, u = 18.5 m/s

acceleration of the race car, a = 2.47 m/s²

distance covered by the race car, s = 79.78 m

Apply the following kinematic equation to determine the final velocity of the race car.

v² = u² + 2as

v² = (18.5)² + 2(2.47)(79.78)

v² = 736.363

v = √736.363

v = 27.14 m/s

Therefore, the final velocity of the racecar is 27.14 m/s

4 0
4 years ago
Does the vertical or horizontal position affect an objects potential energy?
son4ous [18]
Yes. If an object would be vertical, it would most likely have potential energy due to gravity. 
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3 years ago
A weightlifter lifts two 300 newton weights 1.5 meters off the ground. How much work has he done?
alex41 [277]
The Answer Is 900 J
4 0
3 years ago
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