Which mass is undergoing to the greatest amount of acceleration ??
1 answer:
Answer:
Option (3)
Explanation:
Formula used to calculate acceleration is,
F = ma
Where F = force exerted on a mass
m = mass
a = acceleration due to force exerted on the mass
Option (1),
When F = 100 N and m = 100 kg
100 = 100a
a = 1 m per sec²
Option (2)
For F = 1 N and m = 100 kg
1 = 100a
a =
a = 0.01 m per sec²
Option (3)
For F = 100 N and m = 1 kg
100 = 1(a)
a = 100 m per sec²
Option (4)
For F = 1 N and m = 1 kg
1 = 1(a)
a = 1 m per sec²
Therefore. acceleration in Option (3) is the maximum.
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Answer:
The rms voltage (in V) measured across the secondary coil is 459.62 V
Explanation:
Given;
number of turns in the primary coil, Np = 375 turns
number of turns in the secondary coil, Ns = 1875 turns
peak voltage across the primary coil, Ep = 130 V
peak voltage across the secondary coil, Es = ?
The rms voltage (in V) measured across the secondary coil is calculated as;
Therefore, the rms voltage (in V) measured across the secondary coil is 459.62 V
We have that for the Question "A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that the minimum force that must be applied on the <em>book is</em>
- F=44N
From the question we are told
A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal
Generally the equation for the Force is mathematically given as
F=44N
Therefore
the minimum force that must be applied on the <em>book is</em>
F=44N
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