Question

You are studying a population of snapdragon plants on Membata Island. In snapdragons, the dominant allele CR encodes red flowers and the recessive allele CW encodes white flowers. Plants with a heterozygous CRCW genotype have pink flowers. You have counted 10,000 snapdragon plants on Membata Island. You have recorded that 9025 plants have red flowers, 950 plants have pink flowers, and 25 plants have white flowers. If this population is at a Hardy-Weinberg equilibrium, what are the values of p and q in this population

Answer 1

Answer:

we will know that the allelic frequencies are for R 0.95 and r 0.05

Explanation:

We know that the population is in Hardy-Winberg equilibrium, we deduce the following formula:

p + q = 1

p2 + 2pq + q2 = 1

data

R: red flower allele

r: allele blor blanca

p would be equal to the allelic frequency R

q will be equal to the frequency allelic r

2p = RR

2q = rr

2pq = Rr

If there are 25 white flowers in 1000 plants, their frequency will be:

2pq frequency of the Rr genotype

white flower = 25/10000 = 0.0025 = rr = 2q = 0.0025

we deduce that q is equal to 0.05

we replace the data with the previous formula

p + q = 1

p = 1-0.05

we get as a result

  p = 0.95

if p = 0.95 and q = 0.05

we will know that the allelic frequencies are for R 0.95 and r 0.05

Answer 2

Answer:

p = 0.95, q = 0.05

Explanation:

dominant allele CR encodes red flowers = p

the recessive allele CW encodes white flowers = q

Plants with a heterozygous CRCW genotype have pink flowers = 2pq

There are 10,000 snapdragon plants on Membata Island. 9025 plants have red flowers, 950 plants have pink flowers, and 25 plants have white flowers.

To find p = (9025 + 950/2) / 10000 = (9025 + 475) / 10000

p = 0.95

TO find q, use this formular: p+q = 1 since p = 0.95

q = 1-0.95 = 0.05