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3 years ago

What is the length of the diagonal of a square monitor that is 16 inches wide and 16 inches high?

Mathematics

1 answer:

Gennadij [26K]3 years ago

5 0

Answer:

22.63 inches

Step-by-step explanation:

Length of the square monitor = 16 inches

Width of the square monitor = 16 inches

Let the diagonal of the monitor = l inches

Then the square of the diagonal is given by sum of the squares of length and width.

$l^{2}=16^{2}+16^{2}$

$=> l^{2}=256+256$

$=> l^{2}=512$

$=> l=\sqrt{512}$

$=> l=22.63$

Hence the length of the diagonal is 22.63 inches.

You might be interested in

The sum of two consecutive even numbers is 210.

WITCHER [35]

Answer:

104, 106

Step-by-step explanation:

Hello!

A consecutive number is a number that comes after the other.

Let the first even integer be x. Since there is an even integer for every two integers, the second number should be x + 2.

<h3>Solve for x</h3>

(x) + (x + 2) = 210
x + x + 2 = 210
2x + 2 = 210
2x = 208
x = 104

The second number is x + 2, so it would be 106.

6 0

2 years ago

Read 2 more answers

A cylinder has a base diameter of 12in and a height of 17in. What is its volume in cubic in, to the nearest tenths place?

Anna35 [415]

Answer:

1922.7 cubic inches

Step-by-step explanation:

The volume of a cylinder can be found with this formula:

V=πr^2h

The radius, r, is half the diameter.

So, 12/2=6

r=6 inches

Then, just plug the numbers in.

V=π(6)^2(17)

V=1922.65

Rounding to the nearest tenth:

V=1922.7 cubic inches

3 0

2 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 420 green peas and 174 yellow peas. Use a 0.01

slavikrds [6]

Answer:

a) $z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649$

b) For this case we need to find a critical value that accumulates $\alpha/2$ of the area on each tail, we know that $\alpha=0.01$ , so then $\alpha/2 =0.005$ , using the normal standard table or excel we see that:

$z_{crit}= \pm 2.58$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

Step-by-step explanation:

Data given and notation

n=420+174=594 represent the random sample taken

X=174 represent the number of yellow peas

$\hat p=\frac{174}{594}=0.293$ estimated proportion of yellow peas

$p_o=0.23$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of yellow peas is 0.23:

Null hypothesis: $p=0.23$

Alternative hypothesis: $p \neq 0.23$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>3.649)=0.00026$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

b) Critical value

For this case we need to find a critical value that accumulates $\alpha/2$ of the area on each tail, we know that $\alpha=0.01$ , so then $\alpha/2 =0.005$ , using the normal standard table or excel we see that:

$z_{crit}= \pm 2.58$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

5 0

3 years ago

What is one whole and three fourths plus five sixths plus one whole and one fourth

Naddika [18.5K]

Answer:

First of all cant give u the anssswer i am srry but i can give u a hint u need to find eqivelent fractions for the denominators then u can add them

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers