All categories

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics

2 answers:

Nady [450]2 years ago

5 0

Answer:

A) 2x³+11x²+8x-16

Step-by-step explanation:

When you multiply s(x) by t(x) you get something like this:

$s(x) \times t(x) = (2 {x}^{2} + 3x - 4) \times (x + 4) \\ = 2 {x}^{3} + 3 {x}^{2} - 4x + 8 {x}^{2} + 12x - 16 \\ = 2 {x}^{3} + 11 {x}^{2} + 8x - 16$

mars1129 [50]2 years ago

4 0

Answer: A) 2x³ + 11x² + 8x - 16

<u>Step-by-step explanation:</u>

s(x) · t(x) = (x + 4)(2x² + 3x - 4)

= x(2x² + 3x - 4) + 4(2x² + 3x - 4)

= 2x³ + 3x² - 4x + 8x² + 12x - 16

= 2x³ + (3x² + 8x²) + (- 4x + 12x) - 16

= 2x³ + 11x² + 8x - 16

You might be interested in

What the slope of (-15,9) (-10,3)

sweet [91]

The slope is - 3/10

Y over x

6 0

3 years ago

Read 2 more answers

Find the length of the line segment whose endpoints are (-5,6) and (6,6)

umka21 [38]

Answer: 11 units

Step-by-step explanation:

Use the distance formula: $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }$

$(x_{1}, y_{1})=(-5, 6)\\(x_{2}, y_{2})=(6, 6)\\\\\sqrt{(6-(-5)^{2}+(6-6)^{2}} =\sqrt{(11)^{2}+(0)^{2}} =\sqrt{121+0}=\sqrt{121}=11$

5 0

2 years ago

A spherical ball just fits inside a cylindrical can,16 centimeters y'all, with a diameter of 16 centimeters. What is the express

Veseljchak [2.6K]

Answer:

The correct answer is the expression of the volume of the sphere is $\frac{4}{3}$ ×π× $8^{3}$ and the expression of the volume of the leftover space is π× $8^{3}$ ×16 - $\frac{4}{3}$ ×π× $8^{3}$ .

Step-by-step explanation:

Height of the given cylindrical can = 16 cms.

Diameter of the given cylindrical can = 16 cms.

Now a spherical ball just fits in this given cylindrical can. Thus the diameter of the ball is equal to the diameter of the can, equal to 16 cms.

Thus the expression of the volume of ball = $\frac{4}{3}$ ×π× $r^{3}$ = $\frac{4}{3}$ ×π× $8^{3}$

Expression of the volume of the cylindrical can is π× $r^{3}$ × h = π× $8^{3}$ ×16

Expression of the leftover volume would be volume of can minus volume of the ball = π× $8^{3}$ ×16 - $\frac{4}{3}$ ×π× $8^{3}$ .

7 0

2 years ago

The following circular sign is hanging up at ODMS. The diameter of the circle is 20 inches. Which measurement is closest to the

umka21 [38]

I think the answer is B because the radius is 10 and 10 squared is 100 and 100 times 3.14 is 31.4

7 0

2 years ago

How does a digit in the ten thousands place compare to a digit in the thousands place?

Fudgin [204]

A digit in the ten thousands place has 10 times as much value as a digit in the thousands place.

3 0

2 years ago