Answer:
It would be A, C, and D.
Step-by-step explanation:
Answer:
y = -2/3x - 3
Step-by-step explanation:
y = -2/3x + b
-1 = -2/3(-3) + b
-1 = 2 + b
-3 = b
y = -2/3x - 3
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
Read more about distance at
brainly.com/question/1872885
#SPJ1
If you're looking for the solution to the system of equations, here's how we solve using substitution
We know that y = x - 1, so we can plug that into the first equation giving
2x - 3(x-1) = -1
Now distribute the 3 giving 2x - 3x + 3 = -1. After combining like terms we get -x + 3 = -1. Now subtract 3 from both sides, -x = -4, and multiply both sides by -1 to make x positive. x = 4
Now we can plug that into the second equation to get y
y = x - 1, and we know that x = 4, so y = 4 - 1, y = 3. The solution is (4, 3)
Answer:
l = 32.5 units, w= 27.5 units, A = 893.75 units²
Step-by-step explanation:
width is w
length is l = 5+w
P = 2( l+w) , substitute l for 5+w
P = 2(5+w+w)
P = 2(5+2w)
P = 10 +4w
P = 120
10 +4w = 120
4w = 120-10
4w = 110
w= 110/4
w= 27.5 units
l = 5+w = 5+ 27.5 = 32.5 units
A = l*w = 27.5 * 32.5 = 893.75 units ²
